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pickupchik [31]
4 years ago
9

Juan starts walking at 4 miles per hour. An hour and a half later, Cathy starts jogging along the same route at 7 miles per hour

. How long will it take Cathy to catch up with Juan?
Mathematics
2 answers:
kari74 [83]4 years ago
7 0

Answer: it take Cathy 3.75 to catch up with Juan

Step-by-step explanation:

Let t represent the time it will take for Cathy to catch up with Juan. At time t hours when Cathy will catch up Juan, they would have covered the same distance.

Juan starts walking at 4 miles per hour.

Distance = speed × ,time

This means that the distance that Juan covered in to hours would be

4 × t = 4t

An hour and a half later, Cathy starts jogging along the same route at 7 miles per hour. Total time spent by Cathy would be t - 1.5

Distance covered by Cathy would be

7(t - 1.5) = 7t - 10.5

Since the distance covered is the sane, the.

4t = 7t - 10.5

7t - 4t = 10.5

3t = 10.5

t = 10.5/3 = 3.5 hours

kifflom [539]4 years ago
6 0

Answer:

The answer to your question is 2 hours

Step-by-step explanation:

Data

Juan speed = 4 mi/h

Cathy speed = 7 mi/h

t = x

Formula

speed = distance/time

Solve for distance

distance = speed x time

           d = s x t

Distance travelled by Juan

          d = 4t

Distance travelled by Juan in 1.5 h

         d = 4(1.5)

         d = 6 mi

total distance    d = 6 + 4t

Distance travelled by Cathy

         d = vt

         d = 7t

Equal both equations

         6 + 4t = 7t

Solve for t

         6 = 7t - 4t

         6 = 3t

         6/3 = t

         2 = t

Cathy wll catch up with Juan in 2 hours

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\huge\underline{ \underline{ \bf{Answer࿐} }}

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___________________

\boxed{Area =  \frac{1}{2}  \times (a + b) \times h}

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