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UkoKoshka [18]
3 years ago
6

PLEASE HELP 25 POINTS

Mathematics
2 answers:
avanturin [10]3 years ago
7 0

Answer:

The LCM will be: 10x^3y^3

and The Solution will be: \frac{12y^2-5x}{10x^3y^3}

Step-by-step explanation:

We need to solve the problem

\frac{6}{5x^3y}-\frac{1}{2x^2y^3}

Since there is minus sign, so we take LCM of 5x^3y and 2x^2y^3

The LCM will be: 10x^3y^3

Our equation will become after taking LCM

=\frac{12y^2}{10x^3y^3}-\frac{5x}{10x^3y^3}\\=\frac{12y^2-5x}{10x^3y^3}

MrRissso [65]3 years ago
3 0

The lcd would be 10x^3y^3

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Match the following rational expressions to their rewritten forms.
Nookie1986 [14]

Answer:

Answer image is attached.

Step-by-step explanation:

Given rational expressions:

1.\ \dfrac{x^2+x+4}{x-2}\\2.\ \dfrac{x^2-x+4}{x-2}\\3.\ \dfrac{x^2-4x+10}{x-2}\\4.\ \dfrac{x^2-5x+16}{x-2}

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Let us consider the rewritten terms and let us solve them one by one by taking LCM.

(x-2)+\dfrac{6}{x-2}\\\Rightarrow \dfrac{(x-2)^{2}+6 }{x-2}\\\Rightarrow \dfrac{x^2-4x+4+6 }{x-2}\\\Rightarrow \dfrac{x^2-4x+10}{x-2}

So, correct option is 3.

(x+3)+\dfrac{10}{x-2}\\\Rightarrow \dfrac{(x+3)(x-2)+10}{x-2}\\\Rightarrow \dfrac{(x^2+3x-2x-6)+10}{x-2}\\\Rightarrow \dfrac{x^2+x+4}{x-2}

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(x+1)+\dfrac{6}{x-2}\\\Rightarrow \dfrac{(x+1)(x-2)+6}{x-2}\\\Rightarrow \dfrac{x^{2} +x-2x-2+6}{x-2}\\\Rightarrow \dfrac{x^{2} -x+4}{x-2}

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(x-3)+\dfrac{10}{x-2}\\\Rightarrow \dfrac{(x-3)(x-2)+10}{x-2}\\\Rightarrow \dfrac{x^2-3x-2x+6+10}{x-2}\\\Rightarrow \dfrac{x^2-5x+16}{x-2}

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The answer is also attached in the answer area.

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