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3 years ago

The graph below shows the distance, y, in feet, of a mouse from its hole, for a certain amount of time, x, in minutes:

2 answers:

6 0

We have that the initial value of the function is the value at x=0; this is equal to 9. It shows the initial distance from the hole, when no time has passed (x=0). This is so because y has the units of distance. THe slope of the line is the quantity that shows the rate of change, namely how much a change in x is converted to a change in y. This is so because the slope has the units of y/x, namely distance over time (so it shows speed). Correct is b.

serious [3.7K]3 years ago

4 0

The correct answer is;
<span> 9 feet because it represents the original distance of the mouse from its hole </span>

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3. Francis has an unpaid balance of $480 on his credit card.

GarryVolchara [31]

Answer:

4 dollars 80 cents

Step-by-step explanation:

if annual is 12%, find monthly, 12/12=1

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0.01

480*0.01

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6 0

3 years ago

Brandon rode his bike 90% of the distance that Carlee rode her bike this week. Brandon rode 58.5 miles. How many miles did Carle

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Carlee rode 52.65 miles this week.

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3 years ago

Solve this equation zma=a+b ;for a

mina [271]

Subtract b and then a = (zma) - b

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3 years ago

PLEASE HELP step by step

Katen [24]

Answer:

The length of the line segment is 10 units.

Step-by-step explanation:

Let us call the given two points: (x₁, y₁) = (2, -3) and (x₂, y₂) = (8, 5).

The distance between two points, d = $\sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2} }$

Here, $(x_1, y_1) = (2, -3)$ and

$(x_2, y_2) = (8, 5)$

Therefore, distance, d = $\sqrt{(8 - 2)^2 + (5 - (-3))^2$

$= \sqrt{6^2 + 8^2}$

$= \sqrt{36 + 64}$

$= \sqrt{100}$

= 10 units.

Hence, the answer.

3 0

3 years ago

Consider the expressions 3x(x − 2) + 2 and 2x2 + 3x − 18.

Rzqust [24]

Answer:

See answer below

Step-by-step explanation:

For the first expression

3 x (x - 2) + 2 = 3 x^2 - 6 x + 2

evaluated at x= 4 we get: 26

and for x = 5 we get 47.

For the second expression

2 x^2 + 3 x - 18

we get the exact same values when doing the evaluation at these two points.

Based on those results, one may think the expressions may be equivalent, but they are not equivalent. Because at any other x-value, their results are different. See for example that for x = 0 the first one gives "2" while the second one gives -18.

4 0

2 years ago