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notka56 [123]
3 years ago
14

Assume that random guesses are made for seven multiple choice questions on an SAT​ test, so that there are nequals7 ​trials, eac

h with probability of success​ (correct) given by pequals0.55. Find the indicated probability for the number of correct answers. Find the probability that the number x of correct answers is fewer than 4.
Mathematics
1 answer:
olchik [2.2K]3 years ago
7 0

Answer: 0.5438

Step-by-step explanation:

Given : Sample size : n=7

Probability of success​ : p=0.55

Using Normal approximation for binomial distribution , we have

\mu= np =7(0.55)=3.85

\sigma=\sqrt{np(1-p)}=\sqrt{7(0.55)(0.45)}=1.32

The probability that the number x of correct answers is fewer than 4 is given by :-

P(x

Hence, the probability that the number x of correct answers is fewer than 4= 0.5438

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