2 years ago

Math:(

1 answer:

6 0

Answer:

Your friend is incorrect because if you divide 21 by 7 you will get 3 if you add 7 to 3 you get 10 therefore your friend is incorrect.

You might be interested in

Which equation is correct using "is not equal to'' (≠)?

romanna [79]

65/5=13-3=10 27-17=10

72/6=12-1=11 54-43=11

88/8=11-2=9 27-18=9

90/3=30-8=22 34-10=24

So, that makes "90 ÷ 3 − 8 _____ 34 − 10" not equal.

Hope this helps! Stay Safe!

5 0

2 years ago

Ne Shadea part of a whole.

kolbaska11 [484]

Answer:

sorry the equation is confusing

Step-by-step explanation:

and pls fix it and thx.

4 0

2 years ago

How do I solve this using elimination?<br><br> 80x + 45y = 645 <br> x + y = 12

sergeinik [125]

X + y = 12 / x (-45);
Then, -45x - 45y = -540;
We have 80x + 45y = 645 and
-45x - 45y = -540
________________
35x = 105;
Finally, x = 105÷35;
x = 3;
y = 12 - 3;
y = 9;

7 0

2 years ago

Read 2 more answers

If BD is both the altitude and median of ΔABC then ΔABC is _____.

frutty [35]

The answer is C./isoceles

7 0

2 years ago

Four integers are consecutive terms of an arithmetic sequence. The sum of these four numbers is 24 and the product is 945.Find t

Marta_Voda [28]

When common difference, $d=\sqrt{39}$ then the largest term of these four terms will be $6+3\sqrt{39}$

Let four consecutive terms of AP is,

$a-3d, a-d, a+d, a+3d$

Since, sum of all four terms is 24

So, $a-3d+a-d+a+d+a+3d=24\\\\a=6$

And product is 945

So, $(a-3d)(a+3d)(a-d)(a+d)=945\\\\9d^4-360d^2+351=0\\\\d^4-40d^2+39=0\\\\(d^2-1)(d^2-39)=0\\\\d=1,-1\\d=\sqrt{39}, -\sqrt{39}$

When d= 1, -1 then largest term is 9

When $d=\sqrt{39}, -\sqrt{39}$ then largest term is $6+3\sqrt{39}$

Learn more:

https://brainly.in/question/3719232

7 0

1 year ago