The number of permutations of
objects from n objects is

Here 5 digits are chosen from 6 digits without replacement (order important).
The number of 5 digit numbers that can be formed is

Not sure hope you get your answer tho
Answer:
14000 people lived in Brenham
Explanation:
original number shall be always 100%
15% ---> 2100
1% ---> 2100/15
1% ----> 140
100% ---> 140 * 100 = 14000 people
<u><em>Answer:</em></u>
of the paper
<u><em>Explanation:</em></u><u>On Friday:</u>Richard finished 0.25 of the term paper.
<u>This means that:</u>
Remaining = 1 - 0.25 = 0.75 of the paper
<u>On Saturday:</u>Richard finished

of the remainder.
<u>This means that:</u>
Richard finished
<u>Now, for Sunday:</u>We know that Richard finished 0.25 of the paper on Friday and

of the paper on Saturday.
<u>This means that:</u>
Total finished = 0.25 +

=

of the paper
<u>If he wants to finish it by Sunday, then:</u>
He needs to type = 1 -

=

of the paper
Hope this helps :)