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EastWind [94]
3 years ago
10

Five percent of computer parts produced by a certain supplier are defective. what is the probability that a sample of 16 parts c

ontains more than 3 defective ones?
Mathematics
1 answer:
velikii [3]3 years ago
4 0
It is 3 in 320 chance first it's 3/16 then divide by 5%
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Answer:

1/12

Step-by-step explanation:

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A 12-cm-long thin rod has the nonuniform charge density λ(x)=(2.0 nC/cm)e−|x|/(6.0 cm), where x is measured from the center of t
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Answer:

the total charge is

Q=24(1-\exp(-1))nC\approx15.171nC

Step-by-step explanation:

Since x is measured from the center, that means that x=0 is the center so the edges of the rod correspond to x=-6 and x=6. that meas that the total charge can be calculated as

Q=\int^{6}_{-6}2\exp\left(\frac{-|x|}{6}\right)dx

separating the integral from -6 to 0 and from 0 to 6, taking into account that |x|=-x for x<0 and |x|=x for x >=0, we getQ=\int^{0}_{-6}2\exp\left(\frac{x}{6}\right)dx+\int^{6}_{0}2\exp\left(\frac{-x}{6}\right)dx

using the substitution x=-u in the first integral we get\int^{0}_{-6}2\exp\left(\frac{x}{6}\right)dx=-\int^{0}_{6}2\exp\left(\frac{-u}{6}\right)du=\int^{6}_{0}2\exp\left(\frac{-u}{6}\right)du

which is the same as the first integral. Thus, the total charge is given by

Q=2\int^{6}_{0}2\exp\left(\frac{-x}{6}\right)dx

integrating we get

Q=4(-6\exp\left(\frac{-x}{6}\right))\big|^{6}_{0}=-24(\exp(-6/6)-\exp(0))=24(1-\exp(-1))

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