Answer:
a) x=(t^2)/2+cos(t), b) x=2+3e^(-2t), c) x=(1/2)sin(2t)
Step-by-step explanation:
Let's solve by separating variables:
a) x’=t–sin(t), x(0)=1
Apply integral both sides:
where k is a constant due to integration. With x(0)=1, substitute:
Finally:
b) x’+2x=4; x(0)=5
Completing the integral:
Solving the operator:
Using algebra, it becomes explicit:
With x(0)=5, substitute:
Finally:
c) x’’+4x=0; x(0)=0; x’(0)=1
Let 
be the solution for the equation, then:
Substituting these equations in <em>c)</em>
This becomes the solution <em>m=α±βi</em> where <em>α=0</em> and <em>β=2</em>
![x=e^{\alpha t}[Asin\beta t+Bcos\beta t]\\\\x=e^{0}[Asin((2)t)+Bcos((2)t)]\\\\x=Asin((2)t)+Bcos((2)t)](https://tex.z-dn.net/?f=x%3De%5E%7B%5Calpha%20t%7D%5BAsin%5Cbeta%20t%2BBcos%5Cbeta%20t%5D%5C%5C%5C%5Cx%3De%5E%7B0%7D%5BAsin%28%282%29t%29%2BBcos%28%282%29t%29%5D%5C%5C%5C%5Cx%3DAsin%28%282%29t%29%2BBcos%28%282%29t%29)
Where <em>A</em> and <em>B</em> are constants. With x(0)=0; x’(0)=1:
Finally:
Answer:
20 1/2
Step-by-step explanation:
because area equals length times width
Answer:
Mr. Webster's garden is greater than Ms. Turner's garden by 282 sq. yards.
Step-by-step explanation:
Representing the length of the garden by l and width of the garden by w.
For turner's garden, given that l= 24 yards and w= 17 yards.
As the area, A, of the rectangular garden having length l and width w is
So, the area of Ms. Turner's garden, = 24x17=408 sq. yards
For turner's garden, given that l= 5 yards and w= 138 yards.
So, by using equation (i),
the area of Mr. Webster's garden, = 5x138=690 sq. yards
Here, 
, and
= 690-408= 282 sq. yards.
Hence, Mr. Webster's garden is greater than Ms. Turner's garden by 282 sq. yards.
(2x-3)(x+5)
Use foil to simplify, First multiply together the first terms of the pairs, then the outer terms, the middle terms, and finally the last terms. Then combine like terms.
2x^2+10x-3x-15 equals 2x^2+7x-15
The tree would be 15 feet
