The roots of 5x² - 4x + 3 = 0 are non-real
Step-by-step explanation:
In the quadratic equation ax² + bx + c = 0, the discriminant is
b² - 4ac, where a , b , c are constant
- If b² - 4ac ≥ 0, then the roots of the equation are real
- If b² - 4ac < 0, then the roots of the equation are non-real
∵ The quadratic equation is 5x² - 4x + 3 = 0
∵ The general form of the quadratic equation is ax² + bx + c = 0
∴ a = 5
∴ b = -4
∴ c = 3
∵ The discriminant is b² - 4ac
- Substitute the value of a , b and c in the discriminant
∴ b² - 4ac = (-4)² - 4(5)(3)
∴ b² - 4ac = 16 - 60
∴ b² - 4ac = -44
∵ -44 < 0
∴ b² - 4ac < 0
∴ The roots of the equations are non-real
The roots of 5x² - 4x + 3 = 0 are non-real
Learn more:
You can learn more about discriminant in brainly.com/question/8196933
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