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avanturin [10]
3 years ago
11

C

Mathematics
1 answer:
stellarik [79]3 years ago
5 0
Can’t do it need more information
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HELP what is the coefficient of 14x?<br><br> multiplication<br> 14<br> 14x<br> x
cluponka [151]

Coefficient of 14x is 14

Coefficientis the number in front of the letter. For example, coeffient of 2b is 2. When there is no number in front of the letter the coefficient is 1.

3 0
3 years ago
Jose borrows $200 for 2 years at a rate of 8% simple interest calculated annually. How much will he have to pay back at the end
KatRina [158]
Annually= per year

200 at 8% the first year would be
200 • 0.08 = 16 per year
2 years = 32 dollars in interest at the end of 2 years
6 0
3 years ago
Help me plz I can’t figure it out
Aleks04 [339]

Answer:

m = 60

Step-by-step explanation:

The context is very important, the 'm' represents the minutes late the parents are and from this we can eliminate some options :

- The last one because then a parent would drop their child off earlier

- The first one and the third one because it is too long

4 0
2 years ago
The study of fluids​
Elenna [48]

Replace m with 46x10^4 in the equation and solve.

0.036(46x10^4)^3/4 = 635.87

Round to 636

The answer is A.

6 0
2 years ago
Quadrant:
NISA [10]

<h2>✒️Area Between Curves</h2>

\small\begin{array}{ |c|c} \hline \bold{Area\ Between\ Curves} \\ \\ \textsf{Solving for the intersection of }\rm y = x^2 + 2\textsf{ and }\\ \rm y = 4, \\ \\ \qquad \begin{aligned} \rm y_1 &=\rm y_2 \\ \rm x^2 + 2 &=\rm 4 \\ \rm x^2 &= \rm 2 \\ \rm x &=\rm \pm \sqrt{2} \end{aligned} \\ \\ \textsf{We only need the first quadrant area bounded} \\ \textsf{by the given curves so the integral for the area} \\ \textsf{would then be} \\ \\ \boldsymbol{\displaystyle \rm A = \int_{\ a}^{\ b} {\left( \begin{array}{c}\text{upper} \\ \text{function}\end{array} \right) - \left( \begin{array}{c} \text{lower} \\ \text{function} \end{array} \right)\ dx}} \\ \\ \displaystyle \rm A = \int_{0}^{\sqrt{2}} \Big[4 - (x^2 + 2)\Big]\ dx \\ \\ \displaystyle \rm A = \int_{0}^{\sqrt{2}} (2 - x^2)\ dx \\ \\ \rm A = \left[2x - \dfrac{x^3}{3}\right]_{0}^{\sqrt{2}} \\ \\ \rm A = 2\sqrt{2} - \dfrac{\big(\sqrt{2}\big)^3}{3} \\ \\ \rm A = 2\sqrt{2} - \dfrac{2\sqrt{2}}{3} \\ \\\red{\boxed{\begin{array}{c} \rm A = \dfrac{4\sqrt{2}}{3}\textsf{ sq. units} \\ \textsf{or} \\ \rm A \approx 1.8856\textsf{ sq. units} \end{array}}} \\\\\hline\end{array}

#CarryOnLearning

#BrainlyForTrees

\qquad\qquad\qquad\qquad\qquad\qquad\tt{Monday\:at \: 04-04-2022} \\ \qquad\qquad\qquad\qquad\qquad\qquad\tt{12:10 \: pm}

5 0
2 years ago
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