An equation of line with slope m = 5 and which goes through the point (8, -9) is y = 5x - 49
In this question, we have been given a slope of the line and a point (8, -9)
We need to find an equation of the line with slope m = 5 and which goes through the point (8, -9)
Let (x1, y1) = (8, -9)
Using the slope-point form of the line,
y - y1 = m(x - x1)
y - (-9) = 5(x - 8)
y + 9= 5x - 40
y = 5x - 40 - 9
y = 5x - 49
Therefore, an equation of line with slope m = 5 and which goes through the point (8, -9) is y = 5x - 49
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Answer:
658.24 m
Step-by-step explanation:
Let A be the point from where Elton started. Connect points A and C, you get triangle ABC with AB=500 m, BC=350 m and m∠B=100°. Use the cosine rule to determine the length of the segment AC:

DENSITY =MASS/VOLUME
OR MASS = DENSITY X VOLUME
DENSITY =1.5 g/ml AND VOLUME = 10 ml
MASS = 1.5 x 10 = 15 g
Y/4-7=3
y/4=7+3
y/4=10 /4
y=40
Can u guys helpme please!!!