Answer:
300+90+9
-45=0+40+5
Step-by-step explanation:
399-45=354
Answer:
D.) 5x - 2y = 2
Step-by-step explanation:
1. Find all of the options and convert them to slope-intercept form by isolating y. If you isolate y on all of them, you should get that A is y =-2/5x - 1, B is y = 2/5x - 1, C is y = -5/2x - 1, and D is y = 5/2x - 1.
2. Use logic. This line cannot be negative, because negative lines go up to down, not down to up. That cancels out the possibility of A.) and C.) being answers. Now, we know that the slope has to be more than 1 because it is more compressed than that of a line with a slope of 1. The only slope that is more than 1 is D, so that makes D the answer (If you didn't understand this step, go to step 3).
3. Find the slope (This step does not need to be done if you understood Step 2). Take 2 points to be able to find the slope. Two random points on this line are (2,4) and (0,-1). Next, plug them into the formula to find slope. 4-(-1)/2-0 = 5/2, so the slope is 5/2. The only equation with a slope of 5/2 is D. D is the answer.
Answer: D.) 5x - 2y = 2
Answer: x = -100. For you Id say the second one
Step-by-step explanation: multiply both sides, multiply reduce, and multiply.
Answer:
-8
Step-by-step explanation:
2(-2) +3(-2) +2
-4 -6 +2
-10 +2
-8
Answer:
Circumcenter = (4,0)
Circumcircle = √5
Step-by-step explanation:
The circumcentre is the point of intersection of the perpendicular bisectors of a triangle. The vertices of the triangle are equidistant to the circumcentre.
Let us assume the coordinate of the circumcentre is at O(x, y). Therefore the distance between the cirmcumcenter and the vertices are:
AO = BO, therefore
√(x² + y²-4x-2y+5) = √(x² + y² - 10x - 4y + 29)
x² + y²-4x-2y+5 = x² + y² - 10x - 4y + 29
6x + 2y = 24 (1)
BO = CO
√(x² + y² - 10x - 4y + 29) = √(x² + y² - 9x - 8y + 25)
x² + y² - 10x - 4y + 29 = x² + y² - 9x - 8y + 25
-x + 4y = -4 (2)
Multiply equation 2 by 6 and add to equation 1:
26y = 0
y=0
Put y = 0 in -x + 4y = -4
-x + 4(0) = -4
x = 4
The cicumcenter is at (4, 0)
The radius of the circumcircle = AO = BO = CO. Therefore: