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2 years ago

Answer this question for me please cause idk it

Mathematics

1 answer:

Greeley [361]2 years ago

8 0

H=-4.9t^2+25t 0=t(-4.9t+25) T=25÷4.9 T= approx 5.1 which is closes to 5.0 So answer will be 5.0

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Bill has saved $825 from his last 8 paychecks. He saved either $75 or $150 a paycheck. Formulate and solve a system of equations

11Alexandr11 [23.1K]

Answer: 5 times

Step-by-step explanation:

Let the number of times that he saved $75 be x.

Let the number of times that he saved $150 be y.

Therefore, based on the information given in the question, we can form an equation which will be:

x + y = 8 ...... i

75x + 150y = 825 ....... ii

From equation I,

x + y = 8

y = 8 - x....... iiii

Put equation iii into ii and this will be:

75x + 150y = 825

75x + 150(8 - x) = 825

75x + 1200 - 150x = 825

75x - 150x = 825 - 1200

-75x = -375

x = 375/75

x = 5

He saved $75 5times from his paycheck.

4 0

3 years ago

Can someone help me.

marshall27 [118]

Answer:

Step-by-step explanation:

yeah just pick B man lol

7 0

3 years ago

I need Help Fast Asap

Klio2033 [76]

Answer:

C. 7.5

Hope it helps you

7 0

3 years ago

Rewrite 48 + 60 using the distributive property

Flauer [41]

Answer:

12* ( 4+5)

Step-by-step explanation:

48 = 12 * 4

60 = 12 * 5

48 + 60 = 12*4 + 12*5

= 12*( 4 + 5)

= 12* 9

= 108

3 0

3 years ago

Find the equation of the circle with a diameter whose end points are (-1,-2) and (-3,2)

Sergeeva-Olga [200]

Answer:

The equation of the circle with a diameter whose end points are (-1,-2) and (-3,2) is

$x^{2} +y^{2}+4x-1=0$

Step-by-step explanation:

Explanation:-

Step 1:-

The equation of the circle having center and radius is

$(x-h)^2+(y-k)^2=r^2$

here center is (h,k) and radius is r

Given diameter whose end points are (-1,-2) and (-3,2)

The diameter of the circle is passing through the center of the circle

so center of the circle = midpoint of two end points

$(\frac{-1 +(-3) }{2} ,\frac{-2+2 }{2} )$

$(-2,0)$

therefore center (h,k) = (-2,0)

Step 2:-

we have to find the radius of the circle

the radius of the circle = the distance from center to the one end point

i.e., C P = r

Given one end point is P(-3,2) and center C(-2,0)

The distance formula of two points are

$\sqrt{(x_{2}-x_{1} ) ^{2}+ (y_{2}-y_{1} ) ^{2}}$

$r=\sqrt{{(-3)-(-1) ) ^{2}+ (2-(-2)) ^{2}}$

$r=\sqrt{5}$

Step 3:-

center (h,k) = (-2,0) and

radius $r=\sqrt{5}$

The standard form of circle equation

$(x-h)^2+(y-k)^2=r^2$

$(x-(-2))^2+(y-0)^2=\sqrt{5} ^2$

on simplification is

$x^{2} +y^{2}+4 x-1=0$

5 0

3 years ago