Imagine that you are swinging back and forth a chain with a locket on the end. Assuming that you are on Earth so that gravity is
constant at 9.81 meters/second², and you know that the chain is 43 centimeters long, what is the period of this simple pendulum
2 answers:
Time = 2*PI* sq root [(length (in metes) / g (9.81 m / sec^2)]
Time = 2 * PI * sq root [(.43) / 9.81]
Time = 2 * PI * sq root [
<span>
<span>
<span>
0.0438328236
</span>
</span>
</span>
]
Time =
<span>
<span>
<span>
6.2832
</span>
</span>
</span>
* (
<span>
<span>
<span>
0.2093628994
</span>
</span>
</span>
)
Time =
<span>
<span>
<span>
1.3155 seconds
</span></span></span>Please see this page about pendulums:
http://www.1728.org/pendulum.htm
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