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ad-work [718]
3 years ago
9

Imagine that you are swinging back and forth a chain with a locket on the end. Assuming that you are on Earth so that gravity is

constant at 9.81 meters/second², and you know that the chain is 43 centimeters long, what is the period of this simple pendulum
Mathematics
2 answers:
hoa [83]3 years ago
8 0

Answer:

B.  1.3 seconds

erica [24]3 years ago
3 0
Time = 2*PI* sq root [(length (in metes) / g (9.81 m / sec^2)]
Time = 2 * PI * sq root [(.43) / 9.81]
Time = 2 * PI * sq root [ <span> <span> <span> 0.0438328236 </span> </span> </span> ]
Time =  <span> <span> <span> 6.2832 </span> </span> </span> * ( <span> <span> <span> 0.2093628994 </span> </span> </span> )
Time =  <span> <span> <span> 1.3155 seconds

</span></span></span>Please see this page about pendulums:
http://www.1728.org/pendulum.htm


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3 years ago
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anzhelika [568]

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        -------------------------

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Next time, kindly share the answer choices.  Thank you.

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