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2 years ago

Marco made of rectangular prism using 1/2 m cubes the rectangular prism has a volume of 5 m³ how many cubes did Marco use

1 answer:

Nookie1986 [14]2 years ago

8 0

Ok so
1 find volume of 1 cube
2. find total volume of rectangular prism

1/2 m cubes
volume=side^3
side=1/2m (I guess since that was what was given)
v=1/2^3=1/8

so
volume of 1 cube times number of cubes=total volume
1/8m^3 times number of cubes=5m^3
multiply both siides by 8/1 m^3 to clea fraction (since 8/1 times 1/8=8/8=1)
number of cubes=40

needs 40 cubes

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Answer:

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Step-by-step explanation:

The quotient rule for derivation is:

For f(x) = h(x)/k(x)

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In this case, the function is:

f(x) = Sin(x)/(1 + Cos(x))

Then we have:

h(x) = Sin(x)

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And for the denominator:

k(x) = 1 - Cos(x)

k'(x) = -( -Sin(x)) = Sin(x)

Replacing these in the rule, we get:

$f'(x) = \frac{Cos(x)*(1 - Cos(x)) - Sin(x)*Sin(x)}{(1 - Cos(x))^2}$

Now we can simplify that:

$f'(x) = \frac{Cos(x)*(1 - Cos(x)) - Sin(x)*Sin(x)}{(1 - Cos(x))^2} = \frac{Cos(x) - Cos^2(x) - Sin^2(x)}{(1 - Cos(x))^2}$

And we know that:

cos^2(x) + sin^2(x) = 1

then:

$f'(x) = \frac{Cos(x)- 1}{(1 - Cos(x))^2} = - \frac{(1 - Cos(x))}{(1 - Cos(x))^2} = \frac{-1}{1 - Cos(x)}$

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What is the other endpoint if one endpoint is (10,12) and the midpoint is (6,9).?

Lubov Fominskaja [6]

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Step-by-step explanation:

Let $(x_{0},\, y_{0})$ and $(x_{1},\, y_{1})$ denote the two endpoints.

The formula for the midpoint of these two points would be:

$\displaystyle \left(\frac{x_{0} + x_{1}}{2},\, \frac{y_{0} + y_{1}}{2}\right)$ .

(Similar to taking the average of each coordinate.)

In this question, it is given that $x_{0} = 10$ whereas $y_{0} = 12$ . Substitute these two values into the expression for the coordinate of the midpoint: