Which rule represents the translation from the pre-image, ParallelogramABCD, to the image, ParallelogramA'B'C'D'?

Can someone please help me get the answer fo numbers 1,2, and 4?<br>PLEASE HELPPPPP

Gre4nikov [31]

I will help u .........

8 0

3 years ago

I played 4 video games and had an average score of 10,000 points per game.

Verdich [7]

Answer:

Wilt Chamberlain set the single-game scoring record in the National Basketball Association (NBA) by scoring 100 points for the Philadelphia Warriors in a 169–147 win over the New York Knicks on March 2, 1962, at Hershey Sports Arena in Hershey, Pennsylvania. It is widely considered one of the greatest records in basketball. Chamberlain set five other league records that game including most free throws made, a notable achievement, as he was regarded as a poor free throw shooter. The teams broke the record for most combined points in a game (316). That season, Chamberlain averaged a record 50.4 points per game, and he had broken the NBA single-game scoring record (71) earlier in the season in December with 78 points. The third-year center had already set season scoring records in his first two seasons. In the fourth quarter, the Knicks began fouling other players to keep the ball away from Chamberlain, and they also became deliberate on offense to reduce the number of possessions for Philadelphia. The Warriors countered by committing fouls of their own to get the ball back.

The game was not televised, and no video footage of the game has been recovered; there are only audio recordings of the game's fourth quarter. The NBA was not yet recognized as being a major sports league and struggled to compete against college basketball. The attendance at this game was around half of capacity, and no members of the New York press were at the game.

Contents

1 Prologue

2 Game report

2.1 First three quarters

2.2 Breaking records

2.3 Finale

3 Aftermath

4 Legacy

5 Box score

6 See also

7 Notes

8 References

9 External links

Step-by-step explanation:

help u

3 0

3 years ago

Solve the simultaneous equation y-2x+1=0 and 4x^2+3y^2-2xy=7

Lapatulllka [165]

The first equation is $y-2x+1=0$

$y=2x-1$ (Equation 1)

The second equation is $4x^{2}+3y^{2}-2xy=7$ (Equation 2)

Putting the value of x from equation 1 in equation 2.

we get,

$4x^{2}+3(2x-1)^{2}-2x(2x-1)=7$

$4x^{2}+3(4x^{2}+1-4x)-4x^{2}+2x=7$

by simplifying the given equation,

$12x^{2}-10x-4=0$

$6x^{2}-5x-2=0$

Using discriminant formula,

$D=b^{2}-4ac$

$D=25-4 \times 6 \times -2 = 73$

Now the formula for solution 'x' of quadratic equation is given by:

$x=\frac{-b+\sqrt{D}}{2a} and x=\frac{-b-\sqrt{D}}{2a}$

$x=\frac{5+\sqrt{73}}{12} and x=\frac{5-\sqrt{73}}{12}$

Hence, these are the required solutions.

8 0

3 years ago

Degrees Celsius can be converted to degrees Fahrenheit by multiplying 1 and 4/5 and adding 32 degrees C what is 15 degrees C in

Alexxx [7]

Answer:

15C is 59F

Step-by-step explanation:

As an equation, F = (1 4/5)C + 32. 1 and 4/5 is the same as 9/5.

Substitute 15 for C.

F = (9/5)C + 32

F = (9/5)(15) + 32 Multiply 15 by the top number in 9/5

F = 135/5 + 32 Convert 32 to a fraction over 5

F = 135/5 + 160/5 Add the numerators under the same denominator

F = 295/5 Divide

F = 59 Degrees in Farenheit

Therefore 15°C is 59°F.

7 0

3 years ago

Solve each triangle. Round your answers to the nearest tenth.<br>show work If possible

kvasek [131]

<h2>Answer:</h2>

∠ABC = 76°

BC = 20.1

CA = 28.0

<h2>Step-by-step explanation:</h2>

Solving the triangle means finding all unknown angles and sides of the triangle.

(i) Two of the angles (∠BCA = 60° and ∠CAB = 44°) are given. To find the third angle (∠ABC), use one of the theorems stating <em>that the sum of angles of a triangle is equal to 180°.</em>

Therefore, the sum of angles of the triangle ABC is 180°. i.e

∠ABC + ∠BCA + ∠CAB = 180°

=> ∠ABC + 60° + 44° = 180°

=> ∠ABC + 104° = 180°

=> ∠ABC = 180° - 104°

=> ∠ABC = 76°

(ii) One side (BA) of the triangle is given. To get the other sides, we use the sine rule as follows;

=> $\frac{sin60}{25} = \frac{sin44}{BC} = \frac{sin76}{CA}$

=> $\frac{sinBCA}{BA} = \frac{sinCAB}{BC} = \frac{sinABC}{CA}$

<em>Substitute the necessary values</em>

$\frac{sin60}{25} = \frac{sin44}{BC} = \frac{sin76}{CA}$ ---------------------(ii)

(a) To get side BC, use the first two terms of equation (ii)

$\frac{sin60}{25} = \frac{sin44}{BC}$

<em>Cross multiply</em>

BC x sin 60 = 25 x sin 44

BC x 0.8660 = 25 x 0.6947

0.8660 x BC = 17.3675

BC = $\frac{17.3675}{0.8660}$

BC = 20.05

=> BC = 20.1 to the nearest tenth

(b) To get CA, use any two terms of equation (ii). Using the first and third terms, we have;

$\frac{sin60}{25} = \frac{sin76}{CA}$

<em>Cross multiply</em>

CA x sin 60 = 25 x sin 76

CA x 0.8660 = 25 x 0.9703

0.8660 x CA = 24.2575

CA = $\frac{24.2575}{0.8660}$

CA = 28.01

=> CA = 28.0 to the nearest tenth

5 0

3 years ago