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2 years ago

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Erica's Burgers cooks its burgers either well done or medium. Last night the restaurant served 60 burgers in all, 45 of which we

re well done. What percentage of the burgers were well done?

1 answer:

iVinArrow [24]2 years ago

8 0

Answer:

75

Step-by-step explanation:

75 times 60 divided by 100 is 45 and 45 is the amount that were well done

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16+5×4÷2=42 <br><br>insert parentheses to make the statement true

Nat2105 [25]

(16+5)4÷2=42
21×4÷2=42
84÷2=42
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that is were to but you answer

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2 years ago

Describe a real-world situation that can be modeled by the function y=2x-3.

lara [203]

Yes you have a good example.

x = number of cookies

2*x = total amount spent on cookies at $2 each

2x-3 = amount you pay after the $3 discount is applied one time for the entire order

-------------

a more numeric example may be this

Lets say you bought 12 cookies, so x = 12

This means it costs 2*x = 2*12 = 24 dollars total if the discount doesnt apply

However, the 3 dollar discount is there, so the grand total is 24-3 = 21 dollars.

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3 years ago

8.61 X 10^-8 as decimal form. ASAP

ipn [44]

0.0000000861 is your answer

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2 years ago

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Rahul solved the equation 2(x – ) – 2 left-parenthesis x minus StartFraction 1 Over 8 EndFraction right-parenthesis minus StartF

VladimirAG [237]

Answer:

Step 3

Step-by-step explanation:

The solution is given in the image attached. The steps are:

Step 1:

$2x-\frac{1}{4} -\frac{3}{5}x=\frac{55}{4}$

Step 2: simplifying the coefficients of x:

$2x -\frac{3}{5}x-\frac{1}{4}=\frac{55}{4}\\\frac{10x-3}{5} -\frac{1}{4}=\frac{55}{4}\\\frac{7x}{5} -\frac{1}{4}=\frac{55}{4}$

Step 3: Adding 1/4 to both sides

$\frac{7x}{5} -\frac{1}{4}+\frac{1}{4} =\frac{55}{4}+\frac{1}{4}\\ \frac{7x}{5}=\frac{55+1}{4}\\ \frac{7x}{5}=\frac{56}{4}\\$

Step 4: Multiplying both sides by 5/7

$\frac{7x}{5}*\frac{5}{7} =\frac{56}{4}*\frac{5}{7} \\x=10$

The addition property of equality states that if a number is added to both sides of an equation, the equation is still valid (i.e the equation is still the same). From the steps above, The addition property of equality was applied in step 3

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2 years ago

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In two or more complete sentences describe whether or not the given relation represents a function.

vichka [17]

To be a function each x-value (input) should have only one y-value (output). Here you can see when x=2 it has an output of either 5 or 1. Therefore, the relation is NOT a function.

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3 years ago