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Keith_Richards [23]
3 years ago
5

6. Identify the number as rational or irrational. Explain. Type your answers below.

Mathematics
1 answer:
babunello [35]3 years ago
8 0
6. irrational because nothing times itself is 127.
7. a. 29 is the width plus two things that will equal 105 which would be two 52.2 lengths
b. 29, 52.2, 52.2 or 29, 29 69
8. a. 402 - 237(x/15)
b. 11
c. 12
9. no because it does not reach 90 when you add them together
10. rational because the decimal terminates 
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A boat on a river travels downstream between two points, 20 mi apart, in one hour. The return trip against the current takes 2 1
kondaur [170]

Answer:

The speed of boat in still water is 14 miles per hour.

The speed of current is 6 miles per hour.

Step-by-step explanation:

Let v represent the speed of boat in still water and c represent speed of current.

We have been given that a boat on a river travels downstream between two points, 20 miles apart, in one hour.

The speed of boat downstream would speed of boat in still water plus speed of current that is (v+c).

The return trip against the current takes 2 1/ 2 hours. The speed of boat against current would speed of boat in still water minus speed of current that is (v-c).

\text{Speed}=\frac{\text{Distance}}{\text{Time}}

Substituting our given values, we will get:

v+c=\frac{20}{1}...(1)

v-c=\frac{20}{2.5}...(2)

Adding both equations, we will get:

v+c+(v-c)=\frac{20}{1}+\frac{20}{2.5}

v+c+v-c=\frac{20}{1}+\frac{20}{2.5}

2v=20+8

2v=28

\frac{2v}{2}=\frac{28}{2}

v=14

Therefore, the speed of boat in still water is 14 miles per hour.

To find the speed of the current in the river, we will substitute v=14 in equation (1) as:

14+c=\frac{20}{1}

14+c=20

14-14+c=20-14

c=6

Therefore, the speed of current is 6 miles per hour.

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3 years ago
How to solve (-y^2+2y^3+25)/(y-3) using long division
Lubov Fominskaja [6]
Find attached solution.
With Rough Work by the right hand side.
Note that when you carry out the division, you then multiply out with the divisor, (y-3)
I hope this helps.

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