1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Allisa [31]
3 years ago
7

CORRECT GETS BRAINLIEST A pizzeria delivered p pizzas on Thursday. On Friday, it delivered 3 more

Mathematics
1 answer:
Alex73 [517]3 years ago
8 0

Answer:

(p×2)+3

Step-by-step explanation:

I'm not too sure, I've only just started practicing this stuff?

You might be interested in
if 2 more students took the math test and both made a score of , what would the picture graph look like?
Sindrei [870]
I think it would be a dot graph
3 0
3 years ago
Read 2 more answers
3 ft – 7 inches to decimal feet. Record your answer to the nearest hundredth of a<br> foot.
Artemon [7]

3 ft – 7 inches to decimal feet. Record your answer to the nearest hundredth of a foot.  

rounded 2.42 ft

4 0
3 years ago
Find the vertex of the function given below.<br> y = 3x^2+ 6x+1
statuscvo [17]

Answer:

(-1,-2)

Step-by-step explanation:

apex

7 0
3 years ago
If the sum of the even integers between 1 and k, inclusive, is equal to 2k, what is the value of k?
Alisiya [41]
If k is odd, then

\displaystyle\sum_{n=1}^{\lfloor k/2\rfloor}2n=2\dfrac{\left\lfloor\frac k2\right\rfloor\left(\left\lfloor\frac k2\right\rfloor+1\right)}2=\left\lfloor\dfrac k2\right\rfloor^2+\left\lfloor\dfrac k2\right\rfloor

while if k is even, then the sum would be

\displaystyle\sum_{n=1}^{k/2}2n=2\dfrac{\frac k2\left(\frac k2+1\right)}2=\dfrac{k^2+2k}4

The latter case is easier to solve:

\dfrac{k^2+2k}4=2k\implies k^2-6k=k(k-6)=0

which means k=6.

In the odd case, instead of considering the above equation we can consider the partial sums. If k is odd, then the sum of the even integers between 1 and k would be

S=2+4+6+\cdots+(k-5)+(k-3)+(k-1)

Now consider the partial sum up to the second-to-last term,

S^*=2+4+6+\cdots+(k-5)+(k-3)

Subtracting this from the previous partial sum, we have

S-S^*=k-1

We're given that the sums must add to 2k, which means

S=2k
S^*=2(k-2)

But taking the differences now yields

S-S^*=2k-2(k-2)=4

and there is only one k for which k-1=4; namely, k=5. However, the sum of the even integers between 1 and 5 is 2+4=6, whereas 2k=10\neq6. So there are no solutions to this over the odd integers.
5 0
3 years ago
A charity is holding a raffle to raise money. There is one car worth $30,000 and five $100 gift cards being raffled off. Each ti
Dennis_Churaev [7]
There is a total of $35,000 worth of prizes being given out for 5,000 tickets.  We can find the expected value for each ticket by dividing 35,000/5,000.  This equals $7.00.
4 0
4 years ago
Read 2 more answers
Other questions:
  • Among the 1013 respondents, 407 said that pesticides are "not at all annoying". What percentage of respondents said pesticides a
    15·1 answer
  • A set of data consists of 38 observations. how many classes would you recommend for the frequency distribution
    8·1 answer
  • A cone that has volume 1026.25mm^3 and height 20mm. Find the radius of the cone
    15·2 answers
  • 20 points, Thanks to whoever helps! (and brainliest)
    7·1 answer
  • How to find the volume in a cylinder
    8·1 answer
  • Including the bus driver, there are 15 people on a bus. During the bus ride, each person produces 750 BTUs (British Thermal Unit
    11·1 answer
  • This chart shows the growth of a maple tree. If the tree's height increases in this same pattern, what will be the height of the
    15·1 answer
  • 5. What is the mode in this sequence of numbers? 5, 10, 16, 3, 8, 11, 7, 10,2 I a. 8 b. 5 c. 11 d. 10​
    8·1 answer
  • PLEASE HELP ME ASAP?!?!
    15·1 answer
  • A,b,c, or d pls help
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!