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valentina_108 [34]
3 years ago
8

A set of data consists of 38 observations. how many classes would you recommend for the frequency distribution

Mathematics
1 answer:
storchak [24]3 years ago
6 0

solution:

use 2 to the k rule:

2⁵= 32

32 is less than 38,

so,

5 classes are not enough

try the next highest number:

2⁶ = 64

64 is greater than 38 ,

so,

the recommended number of class is 6.

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Suppose that a box contains 7 cameras and that 5 of them are defective. A sample of 2 cameras is selected at random without repl
irinina [24]

Answer:

E(x) = 1.43 (Approx)

Step-by-step explanation:

Given:

Total number of camera = 7

Defective camera = 5

Sample selected = 2

Computation:

when x = 0

P(x=0) = 2/7 × 1/6 = 2/42

P(x=1) = [2/7 × 5/6] + [5/7 × 2/6] = 20/42

P(x=2) = 5/7 × 4/6 = 20/42

So,

E(x) = [0×2/42] + [1×20/42] + [2×20/42]

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3 years ago
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Answer:

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Step-by-step explanation:

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2 years ago
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nordsb [41]

Answer:

Step-by-step explanation:

\frac{5x - 2}{4}+\frac{1}{2}=\frac{3y+2}{2}

Multiply the equation by 4

4*\frac{5x - 2}{4}+4*\frac{1}{2}=4*\frac{3y+2}{2}\\

5x - 2 + 2 = 2*(3y + 2)

5x +0 = 2*3y + 2*2

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\frac{7y+3}{3}=\frac{x}{2}+\frac{7}{3}\\

Multiply the equation by 6

6*\frac{7y+3}{3}=6*\frac{x}{2}+6*\frac{7}{3}\\

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14y + 6 = 3x + 14

14y = 3x + 14 - 6

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Multiply equation (I) by 3 and equation (II) by 5 and then add

(I)*3              15x - 18y = 12

(II)*5           <u>-15x  + 70y = 40</u>     {Now add}

                          52y = 52

                              y = 52/52

                            y = 1

Substitute y =1 in equation (I)

5x - 6*1 =  4

5x - 6 = 4

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7 0
3 years ago
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100 * 0.0022.... = 0.22%

8 0
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