You need PEMDAS
do 3·6 and then 12/6
when you subtract the product and quoetient you get 16 for the answer
1. 9^2
2. 15^3
3. 14^3
4. 11^5
5. 16^4
Solve the problem then state if it's true or false- this is an order of operation problem. 3+2/3(3-X) this is the problem. Now distribute, 3+ 2/3(3)- 2/3(x)= 3+2- 2/3x so the final expression would be 5-2/3x I don't know about the <-7 part but that's the solution to the first one
Answer:

Step-by-step explanation:
We are given:

![interval = [a,b] = [0,2]](https://tex.z-dn.net/?f=interval%20%3D%20%5Ba%2Cb%5D%20%3D%20%5B0%2C2%5D)
Since
⇒ 
Riemann sum is area under the function given. And it is asked to find Riemann sum for the left endpoint.

Note:
If it will be asked to find right endpoint too,

The average of left and right endpoint Riemann sums will give approximate result of the area under
and it can be compared with the result of integral of the same function in the interval given.
So, 

Result are close but not same, since one is approximate and one is exact; however, by increasing sample rates (subintervals), closer result to the exact value can be found.
Answer:
c
9x^ - 30x - 25
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