Answer:
Population in 2013 is 132.76 ≈ 133 million.
Step-by-step explanation:
A country's population in 1990 was 123 million
In 2002 it was 128 million.
We have to calculate the population in 2013.
Since population growth is always represented by exponential function.
It is represented by ![P(t)=P_{0}e^{kt}](https://tex.z-dn.net/?f=P%28t%29%3DP_%7B0%7De%5E%7Bkt%7D)
Here t is time in years, k is the growth constant, and
is initial population.
For year 1990 ⇒
128 =
= ![123e^{12k}](https://tex.z-dn.net/?f=123e%5E%7B12k%7D)
![\frac{128}{123}=e^{12k}](https://tex.z-dn.net/?f=%5Cfrac%7B128%7D%7B123%7D%3De%5E%7B12k%7D)
taking ln on both the sides ⇒
ln ![(\frac{128}{123})= lne^{12k}](https://tex.z-dn.net/?f=%28%5Cfrac%7B128%7D%7B123%7D%29%3D%20lne%5E%7B12k%7D)
ln 128 - ln 123 = 12k [since ln e = 1 ]
4.852 - 4.81218 = 12 k
k = ![\frac{0.03985}{12}=0.00332](https://tex.z-dn.net/?f=%5Cfrac%7B0.03985%7D%7B12%7D%3D0.00332)
For year 2013 ⇒
![P(t)=P_{0}e^{kt}](https://tex.z-dn.net/?f=P%28t%29%3DP_%7B0%7De%5E%7Bkt%7D)
![P(t)=123.e^{(0.00332)(23)}](https://tex.z-dn.net/?f=P%28t%29%3D123.e%5E%7B%280.00332%29%2823%29%7D)
= 123 × ![e^{0.07638}](https://tex.z-dn.net/?f=e%5E%7B0.07638%7D)
= 123 × 1.07937
= 132.76 rounded to 133 million.
Therefore, population in 2013 is 132.76 ≈ 133 million.
Answer:
A negative coefficient just means it is in the denominator of a fraction
Step-by-step explanation:
For example ![5^{-2}= \frac{1}{5^{2} }](https://tex.z-dn.net/?f=5%5E%7B-2%7D%3D%20%5Cfrac%7B1%7D%7B5%5E%7B2%7D%20%7D)
Answer:
why?? ksi ko nhi pta wo kab jai ga...
Step 1 rewrite the equation
step 2 30/5= 6
step 3 x=6
1 solution
Answer:
I believe your answer is C
Hope this helps!