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3 years ago

Meow help me pls :(((

Mathematics

1 answer:

pentagon [3]3 years ago

5 0

Answer:

a) 3x-5=16

b) 30cm

Step-by-step explanation:

a) 5(x-1)=2(x+8)

5x-5=2x+16

5x-2x-5=16

3x-5=16

b) solving the equation gives x=7

put x=7 into first line, 5(7-1)=30cm

to check we can place it into second one as well

2(7+8)=30cm

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What is 6 1/4 x 3 3/5

aliya0001 [1]

Answer:

Step-by-step explanation:

Change mixed fraction to improper fraction. Then reduce to lowest term if possible.

6 1/4 x 3 3/5 = 25/4 * 18/5 = 25* 18 /4*5

= 5 * 18 / 4 {giving by 5th table}

= 5* 9 /2 { giving by 2nd tables}

= 45/2

8 0

3 years ago

there are 300 student and teachers at a sports event.Grade k to 2 is students: 137 Grade 3 to 5 students: 145 Teachers: ? what i

AVprozaik [17]

Answer:

Percentage of teachers = 6%

Step-by-step explanation:

Given;

Number of grade k-2 students = 137

Number of grade 3-5 students = 145

Total = 300

Number of teachers = 300 - (137+145) = 18

Percentage of teachers = (number of teachers÷total)× 100%

%T = (18/300) × 100

%T = 6%

8 0

3 years ago

While waiting for a video game to download, you notice that 30% of 32,000 kilobytes have been downloaded so far.

madam [21]

30%=30/100=0.3

0.3(32,000)=

9600kb downloaded

32 Megabite game? That'll be done is seconds on most connections. (the slowest of connections ive seen are about 20 mb/s)

3 0

4 years ago

A rectangle has width that is 6 meters less than the length. The area of the rectangle is 280 square meters. Find the dimensions

salantis [7]

Dimensions are length 20 meter and width 14 meter

Solution:

Let "a" be the length of rectangle

Let "b" be the width of rectangle

Given that,

A rectangle has width that is 6 meters less than the length

Width = length - 6

b = a - 6

The area of the rectangle is 280 square meters

The area of the rectangle is given by formula:

$Area = length \times width$

Substituting the values we get,

$Area = a \times (a-6)\\\\280 = a^2-6a\\\\a^2-6a -280=0$

Solve the above equation by quadratic formula

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\\quad x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=1,\:b=-6,\:c=-280:\quad a_{1,\:2}=\frac{-\left(-6\right)\pm \sqrt{\left(-6\right)^2-4\cdot \:1\left(-280\right)}}{2\cdot \:1}$

$a =\frac{6 \pm \sqrt{36+1120}}{2}\\\\a = \frac{6 \pm \sqrt{1156}}{2}\\\\a = \frac{6 \pm 34}{2}\\\\Thus\ we\ have\ two\ solutions\\\\a = \frac{6+34}{2} \text{ or } a = \frac{6-34}{2}\\\\a = 20 \text{ or } a = -14$

Since, length cannot be negative, ignore a = -14

Thus solution of length is a = 20

Therefore,

width = length - 6

width = 20 - 6 = 14

Thus dimensions are length 20 meter and width 14 meter

6 0

3 years ago

In the problem 62 × 45, what are the partial products?

Nana76 [90]

In the problem 62 times 45 the partial numbers are 6 and 5

4 0

4 years ago