Question

If a = 1.0 cm, b = 3.0 cm, and i = 30 a, what is the magnitude of the magnetic field at point p?

Answer 1

Answer:

Hence the magnitude for magnetic fied at point p at 3 cm will be 15.7*10^-3 T

Step-by-step explanation:

Given;

Path of current for a conductor with two ends distance as 1 cm and 3 cm

Current=30 A.

To Find:

magnitude of the magnetic field at point p

Solution:

magnitude of the magnetic field at point p=B is given by ,

$B=UI/4pie*r^2$ ]*$\int\limits^a_b {r} \, dx$

Here U  and pie are constants, here a=90 degrees and b=0 degree.

$U=4pie*10^-7$  and r=3cm

Therefore ,

$B=[30*10^-7/3*10^-4]*(pie/2)$

$B=15.7*10^-3$

Hence the magnitude for magnetic fied at point p at 3 cm will be 15.7*10^-3