5^5=5*5*5*5*5=25*25*5=625*5=3125
Answer:
<em>0.615</em>
Step-by-step explanation:
The frequency table is attached below.
We have to calculate, the probability that the student preferred morning classes given he or she is a junior.
i.e ![P(\text{Morning }|\text{ Junior})](https://tex.z-dn.net/?f=P%28%5Ctext%7BMorning%20%7D%7C%5Ctext%7B%20Junior%7D%29)
We know that,
![P(A\ |\ B)=\dfrac{P(A\ \cap\ B)}{P(B)}](https://tex.z-dn.net/?f=P%28A%5C%20%7C%5C%20B%29%3D%5Cdfrac%7BP%28A%5C%20%5Ccap%5C%20B%29%7D%7BP%28B%29%7D)
So,
![P(\text{Morning }|\text{ Junior})=\dfrac{P(\text{Morning }\cap \text{ Junior})}{P(\text{Junior})}](https://tex.z-dn.net/?f=P%28%5Ctext%7BMorning%20%7D%7C%5Ctext%7B%20Junior%7D%29%3D%5Cdfrac%7BP%28%5Ctext%7BMorning%20%7D%5Ccap%20%5Ctext%7B%20Junior%7D%29%7D%7BP%28%5Ctext%7BJunior%7D%29%7D)
Putting the values from the table,
![\dfrac{P(\text{Morning }\cap \text{ Junior})}{P(\text{Junior})}=\dfrac{\frac{16}{143}}{\frac{26}{143}}=\dfrac{16}{26}=0.615](https://tex.z-dn.net/?f=%5Cdfrac%7BP%28%5Ctext%7BMorning%20%7D%5Ccap%20%5Ctext%7B%20Junior%7D%29%7D%7BP%28%5Ctext%7BJunior%7D%29%7D%3D%5Cdfrac%7B%5Cfrac%7B16%7D%7B143%7D%7D%7B%5Cfrac%7B26%7D%7B143%7D%7D%3D%5Cdfrac%7B16%7D%7B26%7D%3D0.615)
Answer:
x=26
Step-by-step explanation:
first rewrite the problem since u know that G(x)=-48
-48=-3/2x-9
second you want to add the 9 to -48 which gives u -39
-39=-3/2x
third you want to times the reciprocal so it would be
-2/3 times -39/1
u can cross out the negatives and turn them into a positive
fourth you can cross cancel 3 and 39 which now the problem looks like this
2/1 times 13/1
which you would times 2 and 13 which your answer would be
26
First, you solve the square root:
![9+ \sqrt{-4}](https://tex.z-dn.net/?f=9%2B%20%5Csqrt%7B-4%7D%20)
Knowing that the square root of a negative number doesn't exist:
![9+ \sqrt{-4}](https://tex.z-dn.net/?f=9%2B%20%5Csqrt%7B-4%7D%20)
![9+2i](https://tex.z-dn.net/?f=9%2B2i)
is your answer.
Hope it helped,
Happy homework/ study/ exam!