Find the centroid of the region that is bounded below by the x-axis and above by the ellipse left parenthesis StartFraction x s
quared Over 4 EndFraction right parenthesis plus left parenthesis StartFraction y squared Over 9 EndFraction right parenthesis equals 1 x2 4 y2 9
1 answer:
Answer with explanation:
The equation of the ellipse is ,whose centroid we have to find is

The curve cuts the x axis at (2,0) and (-2,0) and y axis at (0,3) and (0,-3).
We have to find centroid of the Ellipse on the right of y axis.
Center of gravity will lie on x axis.

![\bar{x}=\frac{\frac{2^2}{2} \times [3-(-3)]}{2*3}\\\\ \bar{x}=\frac{6}{6}\\\\ \bar{x}=1\\\\ \bar{y}=0\\\\ \text{Center of gravity}=(\bar{x},\bar{y})=(1,0)](https://tex.z-dn.net/?f=%5Cbar%7Bx%7D%3D%5Cfrac%7B%5Cfrac%7B2%5E2%7D%7B2%7D%20%5Ctimes%20%5B3-%28-3%29%5D%7D%7B2%2A3%7D%5C%5C%5C%5C%20%5Cbar%7Bx%7D%3D%5Cfrac%7B6%7D%7B6%7D%5C%5C%5C%5C%20%5Cbar%7Bx%7D%3D1%5C%5C%5C%5C%20%5Cbar%7By%7D%3D0%5C%5C%5C%5C%20%5Ctext%7BCenter%20of%20gravity%7D%3D%28%5Cbar%7Bx%7D%2C%5Cbar%7By%7D%29%3D%281%2C0%29)
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