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svetoff [14.1K]
3 years ago
15

6. At Chili’s school, there are 92 freshmen. Every freshman can choose between Latin, Spanish, Italian or no

Mathematics
1 answer:
madam [21]3 years ago
4 0

Use the Venn diagram to solve this question. Start from the common area for three languages. It is known that three languages take 15 freshmen. Then go to the common area for two languages - Spanish and Latin take 12. If 3 persons take only Latin and 36 take Latin, then 36-3-12-15=6 - the number of people that selected Latin and Italian.

4 freshmen take only Spanish, 12 take Spanish and Latin, 15 take all three languages and 42 take Spanish, then 42-12-15-4=11 - the number of people that selected Spanish and Italian.

11 freshmen take Spanish and Italian, 6 take Italian and Latin, 15 take all three languages and 51 take Italian, then 51-11-6-15=19 - the number of people that selected only Italian.

Together 4+12+3+11+15+6+19=70 freshmen. If at school are 92 freshmen, then any of the three language classes take 92-70=22 freshmen.

Answer: only Latin take 3 persons and any of the three language classes take 22 person.

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Previous 20 Two groups leave on different flights from the same airport. Group A flies 200 miles due south, then turns 68° towar
Oksana_A [137]

Answer:

Group B is farther from the airport.

Step-by-step explanation:

To find the distance of each group to the airport we can use the law of cosines in the triangle created with the two movements done and the resulting total distance.

Law of cosines:

c^2 = a^2 + b^2 - 2ab*cos(angle)

For group A, we have the sides of 200 miles and 75 miles, and the angle between the sides is (180-68) = 112°, so the third side of the triangle is:

c^2 = 200^2 + 75^2 -2*200*75*cos(112)

c^2 = 56863.198

c = 238.46\ miles

For group B, we also have the sides of 200 miles and 75 miles, and the angle between the sides is (180-51) = 129°, so the third side of the triangle is:

c^2 = 200^2 + 75^2 -2*200*75*cos(129)

c^2 = 64504.612

c = 253.98\ miles

The distance from group B to the airport is bigger, so group B is farther from the airport.

8 0
4 years ago
Jake made a total of 7 copies at a copy shop, with some being black-and-white copies and some being color copies. Black-and-whit
Arada [10]
Jake spent a total of 70 cents.
b = black-and-white = 8 cents
c = color = 15 cents

70 = 8b + 15c

he made a total of 7 copies
b + c = 7

system of equation:
70 = 8b + 15c
b + c = 7

--------------------------

b + c = 7
b + c (-c) = 7 (-c)
b = 7 - c

plug in 7 - c for b

70 = 8(7 - c) + 15c
Distribute the 8 to both 7 and - c (distributive property)

70 = 56 - 8c + 15c
Simplify like terms

70 = 56 - 8c + 15c
70 = 56 + 7c

Isolate the c, do the opposite of PEMDAS: Subtract 56 from both sides

70 (-56) = 56 (-56) + 7c
14 = 7c

divide 7 from both sides to isolate the c

14 = 7c
14/7 = 7c/7
 c = 14/7
 c = 2

c = 2
---------------

Now that you know what c equals (c = 2), plug in 2 for c in one of the equations.
b + c = 7
c = 2
<em>b + (2) = 7
</em><em />Find b by isolating it. subtract 2 from both sides
b + 2 = 7
b + 2 (-2) = 7 (-2)
b = 7 - 2
b = 5

Jake made 5 black-and-white copies, and 2 color copies

hope this helps
8 0
4 years ago
Read 2 more answers
Find the volume of a cone with base area 16pi ft squared and height 9 ft.
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Answer:

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3 years ago
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13. 5/6+9/11
Juli2301 [7.4K]

Explanation:

Addition of fractions can be accomplished using the formula ...

a/b + c/d = (ad +bc)/(bd)

Usually, you are asked to find the common denominator and rewrite the fractions using that denominator. It is not necessary, but it can save a step in the reduction of the final result. Here, we'll use the formula, then reduce the result to lowest terms.

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13. 5/6 +9/11 = (5·11 +6·9)/(6·11) = 109/66 = 1 43/66

___

14. 7/20 -5/8 = (7·8 -20·5)/(20·8) = -44/160 = -11/40

___

15. 1/5 -1/12 = (1·12 -5·1)/(5·12) = 7/60

___

Dividing fractions can be accomplished different ways. I was taught to multiply by the inverse of the divisor. ("Invert and multiply.") Here, that means the problem (2/7) / (1/13) can be rewritten as ...

(2/7) × (13/1) . . . . . where 13/1 is the inverse of 1/13.

You can also express the fractions over a common denominator. In that case, the quotient is the ratio of the numerators. Perhaps a little less obvious is that you can express the fractions using a common numerator. Then the quotient is the inverse of the ratio of the denominators: (2/7) / (2/26) = 26/7. (You can see how this works if you "invert and multiply" the fractions with common numerators. Those numerators cancel.)

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16. (2/7)/(1/13) = 2/7·13/1 = 26/7 = 3 5/7

8 0
4 years ago
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