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otez555 [7]
3 years ago
13

PLEEEEEASSSEEEHELP ME 6TH GRADE MATH

Mathematics
1 answer:
Airida [17]3 years ago
8 0

Answer:

8-1

Step-by-step explanation:

theres 8 boxes they crossed off one of them, now theres 7

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Mamont248 [21]
The answer is b because the problem is starting that
5 0
3 years ago
How do you solve 38.7×10 to the fourth power
faltersainse [42]

ndex Notation and Powers of 10

10 to the Power 2

The exponent (or index or power) of a number says

how many times to use the number in a multiplication.

102 means 10 × 10 = 100

(It says 10 is used 2 times in the multiplication)

Example: 103 = 10 × 10 × 10 = 1,000

In words: 103 could be called "10 to the third power", "10 to the power 3" or simply "10 cubed"

Example: 104 = 10 × 10 × 10 × 10 = 10,000

In words: 104 could be called "10 to the fourth power", "10 to the power 4" or "10 to the 4"

8 0
4 years ago
Can anyone tell me how you could describe this answer to the equation?
DanielleElmas [232]

The end behavior of the given polynomial is that as x → -∞ or  x → ∞, then, f(x) → 5

<h3>What is the end behavior of the Polynomial?</h3>

We are given the polynomial;

f(x) = 5x/(x - 25)

Now, we want to find the limits as x → ±∞. Let us rearrange the given polynomial to get; f(x) = 5/(1 - (25/x))

Thus, applying limits we have;'

lim x → ±∞ [5/(1 - (25/x))]

From algebraic limit laws we know that;

If f(x) = k, then;

lim x → +∞ [f(x)] = k

Also, lim x → -∞ [f(x)] = k

Thus, applying limits at infinity to our polynomial gives;

lim x → ±∞ [5/(1 - (25/x))] = 5/(1 - 0) = 5

This is because lim x → ∞ for 1/x is 0.

Thus, f(x) has horizontal asymptotes at y = 5

Thus, we conclude that the end behavior is that as x → -∞ or  x → ∞, then, f(x) → 5

Read more about Polynomial End behavior at; brainly.com/question/20347699

#SPJ1

8 0
2 years ago
Which shape shown has only ONE line of symmetry? A) circle B) rectangle C) isosceles trapezoid D) equilateral triangle
Elena L [17]
Triangle is the final answer
6 0
4 years ago
The vertex of the parabola below is at the point (1.-3). Which of the equations below could be the one for this parabola?
Ilia_Sergeevich [38]

Answer: Choice D. y = (x-1)^2 - 3

The vertex is (h,k) = (1,-3). So h = 1 and k = -3.

We have a = 1 as the leading coefficient.

Plug those values into the equation below

y = a(x-h)^2 + k

y = 1(x - 1)^2 + (-3)

y = (x - 1)^2 - 3

3 0
3 years ago
Read 2 more answers
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