For a rectangle, A = LW.
A = (3x + 2)(x - 4)
A = 3x^2 - 12x + 2x - 8
A = 3x^2 -10x - 8
Answer:
(a) yes
(b) no; see below
Step-by-step explanation:
(a) Integer roots of the quartic will be integer divisors of 6. One of the divisors of 6 is 3, so 3 is a possible root.
(b) In order for 3 to be a double root, it would have to be a double factor of 6. The only integer factors of 6 are 1, 2, 3, 6. (3² = 9 is not one.)
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The quartic can be written as ...
k(x -a)(x -b)(x -c)(x -d) . . . . . where a, b, c, d, k are integers
The constant term will be kabcd, of which each of the roots is a factor. If the constant is 6 and one root is d=3, then we must have
kabcd = 3kabc = 6
kabc = 6/3 = 2
Among these four integer factors, there must be an even number of minus signs, and one that has the value ±2. Another root whose value is 3 will not satisfy the requirements.
Answer:
16 total meets
Step-by-step explanation:
it would break even at 8 wins and 8 loss so add them together and get 16 total meets.
Answer:
y=3x-13
Step-by-step explanation:
First, write your equation: y=3x+b. Plug in your ordered pair to the equation, it should look like this: 2=3(5)+b. 3 times 5 equals 15. This is what your equation should look like: 2=15+b. Subtract 15 from both sides to get -13 as your y-intercept. Go back to your original equation and plug in -13 to b. This is your final equation: y=3x-13. Hope this helped!
