Question

14. The diagonals of square ABCD intersect at E. If AE = 2, find the perimeter of ABCD.

Answer 1

Answer:

B, $8\sqrt{2}$

Step-by-step explanation:

Diagonals of a square are congruent so AC= 4

using pythagorean theorem we can then do $x^{2} +x^{2}$=$4^{2}$

$2x^{2} = 16\\x^{2} =8\\x=\sqrt{8} \\x=2\sqrt{2}$

Then for perimeter we times the $2\sqrt{2}$ by 4 and get

$8\sqrt{2}$

Hope this helps and please mark brainliest!!