I depends on the problem i believe.
Given that the hyperbola has a center at (0,0), and its vertices and foci are on y-axis. This, the equation of the hyperbola is of the form
x²/a²-y²/b²=-1 (a>0, b>0)
In the equation, vertices are (0, +/-b) .
Thus,
b=60
Foci (0,+/-√(a²+b²))
thus
√(a²+60²)=65
hence solving for a²
a²=65²-60²
a²=625
a²=25²
hence the equation is:
x²/25²-y²/60²=-1
Answer:
36
Step-by-step explanation:
Answer:
when x = -1, y = -3
when x = -1, y = -1
when x = -1, y = 1
when x = -1, y = 3
Step-by-step explanation:
x = -1; plug in y = 2(-1) - 1 = -2 - 1 = -3
x = 0; plug in y = 2(0) - 1 = 0 - 1 = -1
x = 1; plug in y = 2(1) - 1 = 2 - 1 = 1
x = 2; plug in y = 2(2) - 1 = 4 - 1 = 3
