From the first equation,
x+5 = 3(y+5)
x = 3y + 15 - 5
Now substitue x in the second equation with (3y +15 - 5).
x-5 = 7(y-5)
(3y+15-5) - 5 = 7(y-5)
3y +5 = 7y - 35
-4y = - 40
y = 10
Since y is 10, and x is (3y +15 - 5),
x = 30 + 15 - 5 = 40
Answer:
Linear equation
Step-by-step explanation:
f(x) = 2x + 15
Linear because constant increase
Substitute 136.5 for y.




Compare this equation with 
a = 1, b = - 191, c = 8190
or
or

or

or

or

or

x = 126 or x = 65
Hence, the points on the curve are (65, 136.5) and (126, 136.5).
The width of the air space is the distance between these points.
Width = 
= 
= 126 - 65
= 61
Hence, width of the air space is 61m.
Answer:
36w
Step-by-step explanation:

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Answer:
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