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11Alexandr11 [23.1K]
3 years ago
15

Describe the location of the point that has the following coordinates: negative abscissa, zero ordinate

Mathematics
2 answers:
PSYCHO15rus [73]3 years ago
8 0
The cartesian plane is composed of four quadrants: quadrant I, II, III and IV. Quadrant I has positive x and y axes. Quadrant II has negative x axis and y axis. Quadrant III has both negative x and y axes while quadrant IV has positive x axis and negative y axis. x value refers to the abscissa while y value refers to ordinate. Answer hence is D
e-lub [12.9K]3 years ago
6 0

Answer: The correct location of the point is (d) between Quadrant II and Quadrant III.

Step-by-step explanation:  We are given to select the correct option that describe the location of the point that has the coordinates with negative abscissa and zero ordinate.

On the two dimensional co-ordinate plane (XY - plane), any point with negative abscissa and zero ordinate can be written as

(x, y) = (-a, 0), where a>0.

For example, let us plot (-1, 0), (-2, 0), (-3, 0), etc. on the co-ordinate plane. This is shown in the attached figure.

We notice from the figure that all the points of the form (-a, 0) lie on the negative X-axis.

We know that the negative X-axis lies between Quadrant II and Quadrant III. So, the location of the given point is between Quadrant II and Quadrant III.

Thus, (d) is the correct option.

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4/10 (r/10)

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3 years ago
Find the measure of the angle θ between u and v. Express the answer in radians rounded to two decimal places, if it is not possi
zhuklara [117]

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The measure of the angle θ between u and v = 0.785radians

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The housing market has recovered slowly from the economic crisis of 2008.​ Recently, in one large​ community, realtors randomly
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The 99​% confidence interval for the mean loss in value per home is between $5359 and $13463

Step-by-step explanation:

We are in posession of the sample's standard deviation, so we use the student's t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 45 - 1 = 44

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 44 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.99}{2} = 0.995([tex]t_{995}). So we have T = 2.6923

The margin of error is:

M = T*s = 1505*2.6923 = 4052.

In which s is the standard deviation of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 9411 - 4052 = $5359

The upper end of the interval is the sample mean added to M. So it is 9411 + 4052 = $13463

The 99​% confidence interval for the mean loss in value per home is between $5359 and $13463

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4 years ago
Matthew had a pizza party and was able to buy 8 pizzas for $128. What was the cost per pizza?
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Select all the correct answers.
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A and B

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