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11Alexandr11 [23.1K]
3 years ago
15

Describe the location of the point that has the following coordinates: negative abscissa, zero ordinate

Mathematics
2 answers:
PSYCHO15rus [73]3 years ago
8 0
The cartesian plane is composed of four quadrants: quadrant I, II, III and IV. Quadrant I has positive x and y axes. Quadrant II has negative x axis and y axis. Quadrant III has both negative x and y axes while quadrant IV has positive x axis and negative y axis. x value refers to the abscissa while y value refers to ordinate. Answer hence is D
e-lub [12.9K]3 years ago
6 0

Answer: The correct location of the point is (d) between Quadrant II and Quadrant III.

Step-by-step explanation:  We are given to select the correct option that describe the location of the point that has the coordinates with negative abscissa and zero ordinate.

On the two dimensional co-ordinate plane (XY - plane), any point with negative abscissa and zero ordinate can be written as

(x, y) = (-a, 0), where a>0.

For example, let us plot (-1, 0), (-2, 0), (-3, 0), etc. on the co-ordinate plane. This is shown in the attached figure.

We notice from the figure that all the points of the form (-a, 0) lie on the negative X-axis.

We know that the negative X-axis lies between Quadrant II and Quadrant III. So, the location of the given point is between Quadrant II and Quadrant III.

Thus, (d) is the correct option.

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A company establishes a fund of 120 from which it wants to pay an amount,C, to any of its 20 employees who achieve a high-perfor
Leno4ka [110]

Answer:

C=120/2=60

Step by step Explanation'

To solve this problem, we will need to apply trial-and-error calculation with the binomial distribution, even though it appears like Central Limit Theorem but it's not.

For us to know the value of C , we will look for a minimum integer such that having 'n' number of high performance level of employee has the probability below 0.01.

Determine the maximum value of C, then the maximum value that C can have is 120/n

Let us represent X as the number of employees with high performance with a binomial distribution of

P =0.02( since the percentage of chance of achieving a high performance level is 2%)

n = 20 ( number of employees who achieve a high performance level)

The probability of X= 0 can be calculated

P( X= 0) = 0.98^n

P(X=0)=0.98^20

P(X=0)=0.668

P(X=1)=0.02*20*0.98^19

P(X=1)=0.272

P(X=2)=0.02^2*20*0.98^18

P(X=2)=0.053

Summation of P( X= 0)+ P( X= 1)+P( X= 2) will give us the value of 0.993 which is greater than 0.99( 1% that the fund will be inadequate to cover all payments for high performance.)

BUT the summation of P( X= 0)+ P( X= 1) will give the value of 0.94 which doesn't exceed the 0.99 value,

Therefore, the minimum value of integer in such a way that P(X >2) is less than 0.01 have n= 2

then the maximum value that C can have is 120/n

C=120/2=60

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