Find the measure of the angle θ between u and v. Express the answer in radians rounded to two decimal places, if it is not possi
ble to express it exactly.
1 answer:
Answer:
The question is incomplete as some details are missing; Here is the complete question; If vector u = 3i and v = 4i + 4j, Find the measure of the angle θ between u and v. Express the answer in radians rounded to two decimal places, if it is not possible to express it exactly.
The measure of the angle θ between u and v = 0.785radians
Step-by-step explanation:
The detailed steps is as shown in the attachment.
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For each sub-problem shown below, I'm using the distance formula to compute the distance between the two points
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For the points (-10,2) and (-2,2), the distance is...
d = sqrt((x2-x1)^2+(y2-y1)^2)
d = sqrt((-2-(-10))^2+(2-2)^2)
d = sqrt((-2+10)^2+(2-2)^2)
d = sqrt((8)^2+(0)^2)
d = sqrt(64+0)
d = sqrt(64)
d = 8
------------------------------------------------------
For the points (-3,-1) and (5,1), the distance is...
d = sqrt((x2-x1)^2+(y2-y1)^2)
d = sqrt((5-(-3))^2+(1-(-1))^2)
d = sqrt((5+3)^2+(1+1)^2)
d = sqrt((8)^2+(2)^2)
d = sqrt(64+4)
d = sqrt(68)
------------------------------------------------------
For the points (-3,-2) and (1,3), the distance is...
d = sqrt((x2-x1)^2+(y2-y1)^2)
d = sqrt((1-(-3))^2+(3-(-2))^2)
d = sqrt((1+3)^2+(3+2)^2)
d = sqrt((4)^2+(5)^2)
d = sqrt(16+25)
d = sqrt(41)
------------------------------------------------------
For the points (-3,-5) and (-2,-4), the distance is...
d = sqrt((x2-x1)^2+(y2-y1)^2)
d = sqrt((-2-(-3))^2+(-4-(-5))^2)
d = sqrt((-2+3)^2+(-4+5)^2)
d = sqrt((1)^2+(1)^2)
d = sqrt(1+1)
d = sqrt(2)
------------------------------------------------------
For the points (0,0) and (5,5), the distance is...
d = sqrt((x2-x1)^2+(y2-y1)^2)
d = sqrt((5-0)^2+(5-0)^2)
d = sqrt((5)^2+(5)^2)
d = sqrt(25+25)
d = sqrt(50)
------------------------------------------------------
For the points (1,2) and (1,-10), the distance is...
d = sqrt((x2-x1)^2+(y2-y1)^2)
d = sqrt((1-1)^2+(-10-2)^2)
d = sqrt((0)^2+(-12)^2)
d = sqrt(0+144)
d = sqrt(144)
d = 12
------------------------------------------------------
For the points (1,2) and (5,2), the distance is...
d = sqrt((x2-x1)^2+(y2-y1)^2)
d = sqrt((5-1)^2+(2-2)^2)
d = sqrt((4)^2+(0)^2)
d = sqrt(16+0)
d = sqrt(16)
d = 4
------------------------------------------------------
For the points (2,3) and (10,9), the distance is...
d = sqrt((x2-x1)^2+(y2-y1)^2)
d = sqrt((10-2)^2+(9-3)^2)
d = sqrt((8)^2+(6)^2)
d = sqrt(64+36)
d = sqrt(100)
d = 10
------------------------------------------------------
See the attached image for how the answers match up (take note of the letter labels)
------------------------------------------------------
For the points (-10,2) and (-2,2), the distance is...
d = sqrt((x2-x1)^2+(y2-y1)^2)
d = sqrt((-2-(-10))^2+(2-2)^2)
d = sqrt((-2+10)^2+(2-2)^2)
d = sqrt((8)^2+(0)^2)
d = sqrt(64+0)
d = sqrt(64)
d = 8
------------------------------------------------------
For the points (-3,-1) and (5,1), the distance is...
d = sqrt((x2-x1)^2+(y2-y1)^2)
d = sqrt((5-(-3))^2+(1-(-1))^2)
d = sqrt((5+3)^2+(1+1)^2)
d = sqrt((8)^2+(2)^2)
d = sqrt(64+4)
d = sqrt(68)
------------------------------------------------------
For the points (-3,-2) and (1,3), the distance is...
d = sqrt((x2-x1)^2+(y2-y1)^2)
d = sqrt((1-(-3))^2+(3-(-2))^2)
d = sqrt((1+3)^2+(3+2)^2)
d = sqrt((4)^2+(5)^2)
d = sqrt(16+25)
d = sqrt(41)
------------------------------------------------------
For the points (-3,-5) and (-2,-4), the distance is...
d = sqrt((x2-x1)^2+(y2-y1)^2)
d = sqrt((-2-(-3))^2+(-4-(-5))^2)
d = sqrt((-2+3)^2+(-4+5)^2)
d = sqrt((1)^2+(1)^2)
d = sqrt(1+1)
d = sqrt(2)
------------------------------------------------------
For the points (0,0) and (5,5), the distance is...
d = sqrt((x2-x1)^2+(y2-y1)^2)
d = sqrt((5-0)^2+(5-0)^2)
d = sqrt((5)^2+(5)^2)
d = sqrt(25+25)
d = sqrt(50)
------------------------------------------------------
For the points (1,2) and (1,-10), the distance is...
d = sqrt((x2-x1)^2+(y2-y1)^2)
d = sqrt((1-1)^2+(-10-2)^2)
d = sqrt((0)^2+(-12)^2)
d = sqrt(0+144)
d = sqrt(144)
d = 12
------------------------------------------------------
For the points (1,2) and (5,2), the distance is...
d = sqrt((x2-x1)^2+(y2-y1)^2)
d = sqrt((5-1)^2+(2-2)^2)
d = sqrt((4)^2+(0)^2)
d = sqrt(16+0)
d = sqrt(16)
d = 4
------------------------------------------------------
For the points (2,3) and (10,9), the distance is...
d = sqrt((x2-x1)^2+(y2-y1)^2)
d = sqrt((10-2)^2+(9-3)^2)
d = sqrt((8)^2+(6)^2)
d = sqrt(64+36)
d = sqrt(100)
d = 10
------------------------------------------------------
See the attached image for how the answers match up (take note of the letter labels)