What is one fourth divided by 2

Mathematics

2 answers:

S_A_V [24]3 years ago

8 0

One fourth is the same as 1/4 1. 2 ÷ 4. 1 Reciprocal 1. 1 × 4. 2 Multiply normally. 1/8=answer

Andrew [12]3 years ago

8 0

1/8 is the answer because 2 Divied by 1/4 x 4/1= 8/1 or
1/4divide2=1/4x1/2=1/8

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Bob pays $2 to see a shoe if bob has $4 before the show how much will he have left after the show

SIZIF [17.4K]

Answer:

Step-by-step explanation:

4 - 2 = 2

7 0

3 years ago

B. Determine the values of a and b so that f is continuous. Please help!

wlad13 [49]

Answer:

following are the solution to this question:

Step-by-step explanation:

Please find the complete question in the attached file.

$\lim_{x\to 2}+f(x) = \lim_{x\to 2}+ (ax^2-bx+3) = 4a-2b+3\\\\ \to 4a-2b+3 = 4\\\\ \therefore \ \ 4a-2b = 1\\\\$

The one-sided limits of F(x) at x = 3 must be equivalent for f(x) to be continuous at x = 3.

$\to \lim_{x\to 3}- f(x) = \lim_{x\to 3}- (ax^2-bx+3) = 9a-3b+3\\\\ \to \lim_{x\to 3}+ f(x) = \lim_{x\to 3}+ (2x-a+b) = 6-a+b\\\\$

So,

$\to 9a-3b+3 = 6-a+b\\\\\therefore\\ \to 10a -4b = 3$

$\to 4a - 2b = 1......(a)\\\to 10a - 4b = 3.......(b)\\$

In equation a multiply the by -2 and then add in the equation b:

$\to -8a + 4b = -2\\\to 10a - 4b = 3\\ \to 2a = 1\\\\ \to a = \frac{1}{2}\\\\ \to \ 4(\frac{1}{2}) - 2b = 1\\\\ \to 2 - 2b = 1\\\\ \to -2b = -1\\\\ \to b = \frac{1}{2}$

So, the value of $a \ and \ b= \frac{1}{2}$

4 0

2 years ago

The sculpture consists of five identical prisms. JD says the surface area of the sculpture is 44 times the surface area of one p

larisa86 [58]

The complete question in the attached figure

we know that
(see the attached figure n 2 to understand the problem)
[the surface area of one prism]=2*[x*x]+2*[x*y]+2*[x*y]----> 2x²+4xy
[the surface area of the sculpture]=2*[5*x*y]+2*[3*x*x]+2*[3*x*y]--> 6x²+16xy

now
JD says the surface area of the sculpture is 4 times the surface area of one prism
[the surface area of the sculpture]=4*(2x²+4xy)---> 8x²+16xy

we compare the value that JD says with the real value
(8x²+16xy) > (6x²+16xy)
the value that JD says is greater in comparison with the real value
This is because JD should also subtract the areas of eight hidden surfaces.

the answer is
JD should also subtract the areas of eight hidden surfaces