Find the surface area of the pyramid. the surface area of the pyramid is __in squared.
1 answer:
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Answer:
see explanation
Step-by-step explanation:
1
(a)
If 2 chords of a circle intersect then the product of the measures of the parts of one chord is equal to the product of the measures of the parts of the other chord.
(b)
If 2 secants are drawn from an external point to a circle then the product of the measures of one secant's external part and the entire secant is equal to the product of the measures of the other secant's external part and that entire secant.
(c)
If a tangent and a secant are drawn from an external point to a circle , then the square of the measure of the tangent is equal to the product of the measures of the secant's external part and the entire secant.
2
A radian is defined as the angle subtended at the centre of a circle by an arc equal to the radius of the circle.
1 revolution = 360° = 2π radians
1 radian = ≈ 57°
3
(a)
An inscribed circle of a triangle is a circle drawn inside a circle so the circle barely touches the sides of the triangle.
(b)
The incentre is at the point of intersection of the triangle's 3 angle bisectors.
(c)
A circumscribed circle of a triangle ( circles drawn around the triangle so that the circle passes through each of the triangles's vertices.
(d)
The circumcentre is at the intersection of the perpendicular bisectors of the triangle's sides.
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<h3>Hello there!</h3>
Your answer asks to find the median of the given numbers.
<h3>Answer: B). 9</h3>To find the median, you would need to sort of the numbers from least to greaters.
The given numbers we have:
12, 8, 5, 6, 1, 10, 13, 11
Now, just sort them from least to greatest.
1, 5, 6, 8, 10, 11, 12 ,13
What you would do next is eliminate the numbers on the side, one by one, in order to get your median.
We ended up with two numbers, 8 and 10. Since we didn't end up with one number, we're going to have to add those numbers, and then divide it by two.
You should get 9.
Therefore, the median would be 9.
B). 9 should be your FINAL answer
<h3>I hope this helps!</h3><h3>Best regards, MasterInvestor</h3>