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3 years ago

15.3+1h=1.3−1h solve for h

2 answers:

vladimir1956 [14]3 years ago

6 0

The answer is -7, heres how. start by moving the 15.3 to the other side, giving you 1h= -1h-14. now add 1h to both sides so that they're isolated. 2h= -14. divide by 2. h= -7

Veseljchak [2.6K]3 years ago

3 0

The answer is negative 7

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You have $5,000 to invest for ten years. The Bank pays simple interest at an annual rate of 5%. Calculate your balance after 10

Mazyrski [523]

Answer: $7,500

Step-by-step explanation:

Use the formula: SI = P(1 + rt)

SI = 5000(1 + 0.05[10])

SI = 5000 + 2500

SI = $7,500

After 10 years, your balance should be $7,500

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1 year ago

Find the equation of a line through B(5,2) which is perpendicular to the line 3x+5=0. Hence find the coordinate of the foot of t

Oduvanchick [21]

Answer:

y=2, the equation of a line which is perpendicular to the line 3x+5=0

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Step-by-step explanation:

d1 : 3x+5=0, so 3x=-5, x=-5/3

y=2, the equation of a line which is perpendicular to the line 3x+5=0

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2 years ago

Solve the equation. x − 12.3 = 8.7

lesya [120]

Answer is 3.6
I check it

3 0

2 years ago

Read 2 more answers

Use the Fundamental Theorem of Calculus to find the "area under curve" of

lozanna [386]

Answer:

$\displaystyle A = 300$

General Formulas and Concepts:

Calculus

Integrals

Definite Integrals
Area under the curve
Integration Constant C

Integration Rule [Reverse Power Rule]: $\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C$

Integration Rule [Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)$

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

Integration Property [Addition/Subtraction]: $\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx$

Area of a Region Formula: $\displaystyle A = \int\limits^b_a {[f(x) - g(x)]} \, dx$

Step-by-step explanation:

Step 1: Define

Identify

f(x) = 6x + 19

Interval [12, 15]

Step 2: Find Area

Substitute in variables [Area of a Region Formula]: $\displaystyle A = \int\limits^{15}_{12} {(6x + 19)} \, dx$
[Integral] Rewrite [Integration Property - Addition/Subtraction]: $\displaystyle A = \int\limits^{15}_{12} {6x} \, dx + \int\limits^{15}_{12} {19} \, dx$
[Integrals] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle A = 6\int\limits^{15}_{12} {x} \, dx + 19\int\limits^{15}_{12} {} \, dx$
[Integrals] Integrate [Integration Rule - Reverse Power Rule]: $\displaystyle A = 6(\frac{x^2}{2}) \bigg| \limits^{15}_{12} + 19(x) \bigg| \limits^{15}_{12}$
Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]: $\displaystyle A = 6(\frac{81}{2}) + 19(3)$
Simplify: $\displaystyle A = 300$