Mai-li has 7 1/5 yd. of material. Her new skirt will take 2 3/5 yd. how much material will she have left after the skirt is made
PLEASE HDLP ILL MARK BRAINLIEST
2 answers:
Mai-li would have 2 3/8 material left over. I don't know if this is helpful anymore but here ya go :3.
Answer:
![\texttt{Material left = }=4\frac{3}{5}yd](https://tex.z-dn.net/?f=%5Ctexttt%7BMaterial%20left%20%3D%20%7D%3D4%5Cfrac%7B3%7D%7B5%7Dyd)
Step-by-step explanation:
Mai-li has 7 1/5 yd. of material.
![\texttt{Material Mai-li having = }7\frac{1}{5}=\frac{7\times 5+1}{5}=\frac{36}{5}yd](https://tex.z-dn.net/?f=%5Ctexttt%7BMaterial%20Mai-li%20having%20%3D%20%7D7%5Cfrac%7B1%7D%7B5%7D%3D%5Cfrac%7B7%5Ctimes%205%2B1%7D%7B5%7D%3D%5Cfrac%7B36%7D%7B5%7Dyd)
Her new skirt will take 2 3/5 yd.
![\texttt{Material needed for skirt = }2\frac{3}{5}=\frac{2\times 5+3}{5}=\frac{13}{5}yd](https://tex.z-dn.net/?f=%5Ctexttt%7BMaterial%20needed%20for%20skirt%20%3D%20%20%7D2%5Cfrac%7B3%7D%7B5%7D%3D%5Cfrac%7B2%5Ctimes%205%2B3%7D%7B5%7D%3D%5Cfrac%7B13%7D%7B5%7Dyd)
Material left = Material Mai-li having - Material needed for skirt
![\texttt{Material left = }\frac{36}{5}-\frac{13}{5}=\frac{36-13}{5}=\frac{23}{5}\\\\\texttt{Material left = }\frac{20+3}{5}=4\frac{3}{5}yd](https://tex.z-dn.net/?f=%5Ctexttt%7BMaterial%20left%20%3D%20%7D%5Cfrac%7B36%7D%7B5%7D-%5Cfrac%7B13%7D%7B5%7D%3D%5Cfrac%7B36-13%7D%7B5%7D%3D%5Cfrac%7B23%7D%7B5%7D%5C%5C%5C%5C%5Ctexttt%7BMaterial%20left%20%3D%20%7D%5Cfrac%7B20%2B3%7D%7B5%7D%3D4%5Cfrac%7B3%7D%7B5%7Dyd)
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