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lord [1]
4 years ago
12

PLZ HURRY IT'S URGENT!!!!!

Mathematics
1 answer:
Korvikt [17]4 years ago
4 0

Answer:

the answer you are looking for is -11s

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Which graph represents the function r(x) = Ix-21 - 1
Gelneren [198K]

Answer:

the one you already have marked (a)

A is correct

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
√-2.56<br> find the real-number root
alisha [4.7K]
1.6 i am pretty sure e
4 0
3 years ago
4-t=3(t-1)-5<br> I really need steps, the variable in the parentheses is seriously confusing me.
Alekssandra [29.7K]
4 - t = 3(t - 1) - 5

= 4 - t = (3t - 3) - 5
= 4 - t = 3t - 8

Add 8 to both sides:
12 - t = 3t

Add t on both sides:
12 = 4t

Divide both sides by 4:
t = 3 

Hope I helped :)

EDIT: Yeah I see where I went wrong - answer is 3


6 0
3 years ago
Read 2 more answers
Write an equation of the line that is perpendicular to 3x + 9y = 7 and passes through the point (6, 4)
andrezito [222]
The perpendicular line will have the x and y coefficients swapped and one of them negated. We can write the desired line as
  9(x -6) -3(y -4) = 0
where the coordinates of the point of interest are (6, 4).
Dividing by 3, this is
  3(x -6) -(y -4) = 0
  3x -y = 14

An equation for the line of interest is ...
  3x -y = 14

8 0
3 years ago
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A manufacturer of chocolate chips would like to know whether its bag filling machine works correctly at the 439.0 gram setting.
Vlada [557]
<h2>Answer with explanation:</h2>

Let \mu be the average weight of chocolate chips in each bag.

As per given , we have

H_0: \mu =439.0\\\\ H_a: \mu

Since H_a is left-tailed , so we perform a left-tailed test.

Also, the population standard deviation is known \sigm=21.0.

So we use z-test.

Test statistic : z=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqt{n}}}

Substitute given value ,\overline{x}=433.0\ , n=47,\ \sigma=21 \ , \mu=439

z=\dfrac{433-439}{\dfrac{21}{\sqrt{47}}}\approx-1.96

Significance level = 0.05

Decision rule : Reject H_0 when p-value < 0.05.

By z-table , P- value for left-tailed test  = P(z<-1.96)= 1- P(z<1.96)

[∵ P(Z<-z)=1-P(Z<z)]

= 1- 0.9750

=0.025

Since , P-value(0.025) < 0.05 , so we reject the null hypothesis.

We support the claim that the machine is underfilling the bags at 0.05 significance level .

3 0
3 years ago
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