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Gemiola [76]
3 years ago
10

What is the equation of the line that is parallel to the line y = 3x - 4 and passe

Mathematics
1 answer:
lara31 [8.8K]3 years ago
8 0

Answer:

B. y= 3x -14

Step-by-step explanation:

To find the equation of a line that is parallel  to the line y = 3x - 4 and passe

through the point (4,-2), we will follow the steps below;

Equation of a line is y=mx + c

where m is the slope and c is the intercept

To find the slope of the new equation, we will compare y =mx + c and y=3x - 4

The slope of the equation y = 3x-4 is 3

line that are parallel have the same slope, so the slope of the new equation is also m = 3

To find the intercept, we will substitute x=4,  y = -2 and m =4 into the formula y =mx + c then solve for c

That is;

y = mx + c

-2 = 3(4) + c

-2 = 12 + c

subtract 12 from both-side of the equation

-2-12 = 12-12 + c

-14 = c

c= -14

we can now substitute m and c into the formula to form the new equation

y = mx + c

y = 3x -14

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