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The end behavior of the graph of f(x) = -0.25x2 - 2x + 1 is that A) As x increases, f(x) increases. As x decreases, f(x) decreases.
<h3>What is the end behavior about?</h3>The end behavior of a function f tells us that the way that the graph function behaves at the "ends" of the x-axis.
Note that the end behavior of a function tells the trend of the graph and in this graph, f(x) -----> +∞ as x----> -∞ (as the value of x decreases the value of f(x) increases) and f(x) -----> -∞ as x----> +∞ (as the value of x increases the value of f(x) decreases).
Therefore, The end behavior of the graph of f(x) = -0.25x2 - 2x + 1 is that A) As x increases, f(x) increases. As x decreases, f(x) decreases.
See full question below
What is the end behavior of the graph of f(x) = -0.25x2 - 2x + 1?
A) As x increases, f(x) increases. As x decreases, f(x) decreases.
B) As x increases, f(x) decreases. As x decreases, f(x) decreases.
C) As x increases, f(x) increases. As x decreases, f(x) increases.
D) As x increases, f(x) decreases. As x decreases, f(x) increases
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<u>Answer-</u>
<em>The correct answer is</em>
<em>∠BDC and ∠AED are right angles</em>
<u>Solution-</u>
In the ΔCEA and ΔCDB,
As this common to both of the triangle.
If ∠BDC and ∠AED are right angles, then
Now as
∠BCD = ∠ACE and ∠BDC = ∠AED,
∠DBC and ∠EAC will be same. (as sum of 3 angles in a triangle is 180°)
Then, ΔCEA ≈ ΔCDB
Therefore, additional information can be used to prove ΔCEA ≈ ΔCDB is ∠BDC and ∠AED are right angles.