All categories

2 years ago

HELP PLEASE!!!! what is the midpoint of (-5,-5) and (-1, -1)

Mathematics

2 answers:

Andreas93 [3]2 years ago

7 0

(-3,-3) is your answer please give brainliest!

RoseWind [281]2 years ago

6 0

Answer:

(-3,-3)

Step-by-step explanation:

You might be interested in

If t=0 in 1980, find the value of A. Round answer to the nearest million.

balu736 [363]

P=Ae^kt

225 = 210 * e^(k*(1990-1980)

225/210=e^10k ln(225/210)=10k

k=ln(225/210)/10=0.0069

P = 210*e^(0.0069t)

for 2000 ===> t = 2000-1980=20

P = 210*e^(0.0069*20)

P=241.0749=241

4 0

3 years ago

Which is the best estimate for 37% of 293?

Trava [24]

A.75
37% of 293 is 108.41 so ya

7 0

3 years ago

Read 2 more answers

A force of 10 lb is required to hold a spring stretched 4 in. beyond its natural length. How much work is done in stretching it

Troyanec [42]

Answer:

W = 15/4 ft . ib

Step-by-step explanation:

Force = 10ib

According to hooked law, f(x) = kx

x = 4inches = 4/12 ft

x= 1/3ft

f(x) = 1/3k

10 = 1/3k

k = 30 ib/ft

f(x) = 30x

Workdone = integral of f(x) with its limit

6 inches = 6/12 ft

= 1/2ft

W = integral(1/2 to 0) of 30x

W = 15x^2(1/2 to 0)

W = 15(1/2)^2 - 15(0)^2

W = 15(1/4) - 0

W = 15/4 ft. Ib

4 0

3 years ago

twinlakes on the shelf of a covenience store lose their fresh tastines over time. we say that the taste quality is 1 when the tw

Zolol [24]

Answer:

The graph is shown below.

The time to make the taste to half is <u>4.265 s.</u>

Step-by-step explanation:

Given:

Initial value of the taste is, $Q_0=1$

Therefore, the quality of taste over time 't' is given as:

$Q(t)=Q_0(0.85)^t\\Q(t)=1(0.85)^t$

Now, when the taste reduces to half, $Q=0.5$

Therefore,

$0.5=1(0.85)^t$

Taking natural log on both the sides, we get:

$\ln(0.5)=\ln(0.85)^t\\\ln(0.5)=t\ln(0.85)\\t=\frac{ln(0.5)}{\ln(0.85)}=4.265\ s$

Therefore, the time to make the taste to half is <u>4.265 s.</u>

4 0

2 years ago

Arc AB is One-sixth of the circumference of a circle. What is the radian measure of the central angle? StartFraction pi over 6 E

oksian1 [2.3K]

Answer:

StartFraction pi Over 3 EndFraction

Step-by-step explanation:

we know that

The circumference of a circle subtends a central angle of 360 degrees or 2π radians

by proportion

Find out the central angle for an arc equal to One-sixth of the circumference of a circle

Let

x -----> the measure of the central angle in radians for an arc equal to One-sixth of the circumference

$\frac{C}{2\pi}=\frac{(C/6)}{x}\\\\x=2\pi(C/6)/C\\\\x=\frac{2\pi}{6}$

Simplify

$x=\frac{\pi}{3}$

therefore

StartFraction pi Over 3 EndFraction

5 0

2 years ago

Read 2 more answers