Question

Write the equation of the line with slope 3 that passes through the point (-1,6) in slope intercept form.

Answer 1

For this case we have that by definition, the equation of a line of the slope-intersection form is given by:

$y = mx + b$

Where:

m: It's the slope

b: It is the cut-off point with the y axis

According to the statement data we have:

$m = 3$

Thus, the line is of the form:

$y = 3x + b$

We substitute point $(-1,6)$ and find "b":

$6 = 3 (-1) + b\\6 = -3 + b\\6 + 3 = b\\b = 9$

Finally, the equation is:

$y = 3x + 9$

Answer:

$y = 3x + 9$