6%(5) = .30 6%
...........................................
Answer:
Rhombus
Step-by-step explanation:
The given points are A(−5, 6), B(−1, 8), C(3, 6), D(−1, 4).
We use the distance formula to find the length of AB.



The length of AD is



The length of BC is:



The length of CD is



Since all sides are congruent the quadrilateral could be a rhombus or a square.
Slope of AB
Slope of BC 
Since the slopes of the adjacent sides are not negative reciprocals of each other, the quadrilateral cannot be a square. It is a rhombus
Answer:
Net Area = 168
Step-by-step explanation:
See attachment for complete question
I'll make reference to the attachment, when needed.
The shapes that make up the net are labelled 1 to 5.
So, to calculate the surface area of the net, we simply calculate the surface area of each label.
Label 1: Rectangle
Area = Length * Width
Area = 10 * 5
Area = 50
Label 2: Rectangle
Area = Length * Width
Area = 8 * 5
Area = 40
Label 3: Rectangle
Area = Length * Width
Area = 6 * 5
Area = 30
Label 4: Triangle
Area = ½Base * Height
Base = 6 and Height = 8
So:
Area = ½ * 6 * 8
Area = 24
Label 5: Triangle
Area = ½Base * Height
Base = 6 and Height = 8
So:
Area = ½ * 6 * 8
Area = 24
So, the net area is the summation of the calculated areas of label 1 to 5
Net Area = 50 + 40 + 30 + 24 + 24
Net Area = 168
6 x 532 in expanded form is 6 x 500 + 30 + 2