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astraxan [27]
3 years ago
14

Which statement is true about the difference 2√7-√28

Mathematics
1 answer:
maw [93]3 years ago
7 0
It seems like there are answer choices but you forgot to post them. If you want to simplify then

2*sqrt(7) - sqrt(28) = 2*sqrt(7) - sqrt(4*7)
2*sqrt(7) - sqrt(28) = 2*sqrt(7) - sqrt(4)*sqrt(7)
2*sqrt(7) - sqrt(28) = 2*sqrt(7) - 2*sqrt(7)
2*sqrt(7) - sqrt(28) = (2-2)*sqrt(7)
2*sqrt(7) - sqrt(28) = (0)*sqrt(7)
2*sqrt(7) - sqrt(28) = 0

So the whole complicated expression simplifies to 0 (zero)

This is because sqrt(28) = 2*sqrt(7) when you simplify sqrt(28)

Side Note: "sqrt" is shorthand for "square root"

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The function f(x) = –x2 – 4x + 5 is shown on the graph. On a coordinate plane, a parabola opens down. It goes through (negative
sertanlavr [38]

The true statement about the function f(x) = -x² - 4x + 5 is that:

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<h3 /><h3>What is the domain and range for the function of y = f(x)?</h3>

The domain of a function is the set of given values of input for which the function is valid and true.

The range is the dependent variable of a given set of values for which the function is defined.

  • The domain of the function: f(x) = -x² - 4x + 5 are all real number from -∞ to +∞

For a parabola ax² + bx + c  with the vertex \mathbf{(x_v,y_v)}

  • If a < 0, then the range is f(x) ≤ \mathbf{y_v}
  • If a > 0, then the range f(x) ≥  \mathbf{y_v}
  • Here; a = -1,

The vertex for an up-down facing parabola for a function y = ax² + bx + c is:

\mathbf{x_v = -\dfrac{b}{2a}}

Thus,

  • vertex \mathbf{(x_v,y_v)} = (-2, 9)

Range: f(x) ≤ 9

Therefore, we can conclude that the range of the function is all real numbers less than or equal to 9.

Learn more about the domain and range of a function here:

brainly.com/question/26098895

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2 years ago
The numbers on a football field indicate 10 yard increments. You walk around the perimeter of a football field between the pylon
Roman55 [17]

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5,333 square yards.

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The area of the playing field is 5,333 square yards.

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3 years ago
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