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astraxan [27]
3 years ago
14

Which statement is true about the difference 2√7-√28

Mathematics
1 answer:
maw [93]3 years ago
7 0
It seems like there are answer choices but you forgot to post them. If you want to simplify then

2*sqrt(7) - sqrt(28) = 2*sqrt(7) - sqrt(4*7)
2*sqrt(7) - sqrt(28) = 2*sqrt(7) - sqrt(4)*sqrt(7)
2*sqrt(7) - sqrt(28) = 2*sqrt(7) - 2*sqrt(7)
2*sqrt(7) - sqrt(28) = (2-2)*sqrt(7)
2*sqrt(7) - sqrt(28) = (0)*sqrt(7)
2*sqrt(7) - sqrt(28) = 0

So the whole complicated expression simplifies to 0 (zero)

This is because sqrt(28) = 2*sqrt(7) when you simplify sqrt(28)

Side Note: "sqrt" is shorthand for "square root"

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There are 1295 students attending a small university there are 714 woman in rolled what percentage of students are woman
MatroZZZ [7]

Answer:

Approximately 55% of enrolled students are women.

Step-by-step explanation:

To find the percentage of a given set of data, you need to divide the number of actual students by the total number of students.  In this case, they are wanting the percentage of just women students at the university:

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4 0
3 years ago
In how many ways can a committee of 5 people be chosen from a total of 30 possible people?
Stolb23 [73]

Answer:  142506

Step-by-step explanation:

Given : The total number of choices for people in committee = 30

The number of people need to be chosen =5

Since , here order doesn't matter, so we use combination.

The combination of r things taking from n at a time is given by :-

C(n,r)=\dfrac{n!}{(n-r)!r!}

Now, the number of possible combinations of 5 people be chosen from a total of 30 possible people :-

C(30,5)=\dfrac{30!}{(30-5)!5!}\\\\=\dfrac{30\times29\times28\times27\times26}{120}\\\\=142506

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3 0
3 years ago
Rotate the figure 90 degrees about vertex A.
ziro4ka [17]

Answer:

A' is (1,1) B is (4,1) C is (1,-1)

Step-by-step explanation:

Since we rotating the figure about point a, we know a is the center of the rotation meaning no matter how far we rotate point a new image will stay on where point a pre image was which in this case is (1,1). Also since we know the rules of rotating a angle 90 degrees About the origin we are going to translate the figure to have the one point we are rotating about at the orgin. Since translations are a rigid transformations, the figure will stay the same A. Move the figure 1 to the left and 1 down so A becomes 0,0 B becomes 0,3 and C becomes 2,0. Then apply the rules of 90 degree clockwise rotation rules. (x,y) goes to (y,-x) . A stays (0,0) B becomes (3,0) and C becomes (0,-2). Then translate the figure 1 to the right and 1 down since we rotating about point a which is 1,1 and it at 0,0 rn. A' is 1,1. B' becomes (4,1). C' becomes (1,-1).

5 0
3 years ago
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