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gavmur [86]
3 years ago
14

Match the fractions that are equivalent to each other?

Mathematics
2 answers:
k0ka [10]3 years ago
6 0

Answer:

1 and a

2 and b

3 and c

4 and d

MrRissso [65]3 years ago
4 0

Answer:

1&a 2&b 3&c 4&d

Step-by-step explanation:

...

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PLEASE HELP ME!! Math
IgorLugansk [536]

Answer: D

Step-by-step explanation:

3 0
3 years ago
Whats 5x2+500=844.45
Triss [41]
5x2 + 500 = 844.45, solving for x.

Subtract 500 from both sides: 5x2 = 344.45

Simplify (5*2): 10x = 344.45

Divide 10 from both sides: x = 34.45 (rounded)
3 0
3 years ago
Read 2 more answers
A package is secured with ribbon. Two pieces of ribbon,
lutik1710 [3]

Answer:

A total of 387 centimeters of ribbon are used.

Step-by-step explanation:

We already know that two out of three pieces of ribbon are 1.25 meters.

The third piece of ribbon is 120 millimeters (mm) longer.

1 millimeters = 0.001 meters

120 x 0.001 = 0.12

That means that the third piece of ribbon is 0.12 meters longer than the first two. The length of the third ribbon is 1.25 m + 0.12 m = 1.37 m

In order to find the total number of meters of ribbon used, we need to do addition.

1.25 m + 1.25 m + 1.37 m = 3.87 m

But, the question is asking us the number of centimeters of ribbon that are used.

1 m = 100 cm

3.87 x 100 = 387 cm

Therefore, a total of 387 centimeters of ribbon are used.

Hope this helps! Have a blessed day! :)

7 0
2 years ago
element X is a radioactive isotope such that every 21 years, its mass decreases by half. Given that the initial mass of a sample
pashok25 [27]

Answer:

The percentage rate of decay per year is of 3.25%.

The function showing the mass of the sample remaining after t is A(t) = 80(0.9675)^t

Step-by-step explanation:

Equation for decay of substance:

The equation that models the amount of a decaying substance after t years is given by:

A(t) = A(0)(1-r)^t

In which A(0) is the initial amount and r is the decay rate, as a decimal.

Every 21 years, its mass decreases by half.

This means that A(21) = 0.5A(0). We use this to find r, the percentage rate of decay per year.

A(t) = A(0)(1-r)^t

0.5A(0) = A(0)(1-r)^{21}

(1-r)^{21} = 0.5

\sqrt[21]{(1-r)^{21}} = \sqrt[21]{0.5}

1 - r = 0.5^{\frac{1}{21}}

1 - r = 0.9675

r = 1 - 0.9675 = 0.0325

The percentage rate of decay per year is of 3.25%.

Given that the initial mass of a sample of Element X is 80 grams.

This means that A(0) = 80

The equation is:

A(t) = A(0)(1-r)^t

A(t) = 80(1-0.0325)^t

A(t) = 80(0.9675)^t

The function showing the mass of the sample remaining after t is A(t) = 80(0.9675)^t

8 0
3 years ago
Read 2 more answers
Can someone give me the answers please?
lutik1710 [3]

Answer:

6. slope= -4/5     Y-intercept is 3

7.

a.y=-2x

b.y=1x+1

c.5/2x-1

d.y=4x+3

e.y=-3/2x-5

Step-by-step explanation:

3 0
3 years ago
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