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gavmur [86]
3 years ago
14

Match the fractions that are equivalent to each other?

Mathematics
2 answers:
k0ka [10]3 years ago
6 0

Answer:

1 and a

2 and b

3 and c

4 and d

MrRissso [65]3 years ago
4 0

Answer:

1&a 2&b 3&c 4&d

Step-by-step explanation:

...

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K-3k²-3k+2k²<br><br><br>what is the answer<br>please help me​
laiz [17]

Answer:

Assuming you want to simplify the expression, it can be shortened to:

-k² - 2k

Step-by-step explanation:

What you need to do here is called grouping like terms.  Like terms can be described as terms that have the same factors.  In this case, the factors we're looking at are k and k²:

Given:

k - 3k² -3k + 2k²

We'll rearrange to group like expressions:

= -3k² + 2k² + k -3k

Pull out common factors:

= (-3 + 2)k² + (1 - 3)k

And simplify:

= -k² - 2k

5 0
3 years ago
What is the true solution to 3 in 2 + in 8 = 2 in (4x)
11Alexandr11 [23.1K]
The first step for solving this equation is to determine the defined range.
3㏑(2) + ㏑(8) = 2㏑(4x), x > 0
Write the number 8 in exponential form.
3㏑(2) + ㏑(2³) = 2㏑(4x)
Using ㏑(a^{x}) = x × ㏑(a),, transform the expression.
3㏑(2) + 3㏑(2) = 2㏑(4x)
Now collect the like terms on the left side of the equation.
6㏑(2) = 2㏑(4x)
Switch the sides of the equation.
2㏑(4x) = 6㏑(2)
Using x × ㏑(a) = ㏑(a^{x}),, transform the expression on the left side of the equation.
㏑((4x)²) = 6㏑(2)
Using x × ㏑(a) = ㏑(a^{x}),, transform the expression on the right side of the equation.
㏑((4x)²) = ㏑(2^{6})
Since the bases of the logarithms are the same,, you need to set the arguments equal.
(4x)² = 2^{6}
Take the square root of both sides of the equation and remember to use both the positive and negative roots.
4x = +/- 8
Now separate the equation into 2 possible cases.
4x = 8
4x = -8
Solve the top equation for x.
x = 2
Solve the bottom equation for x.
x = 2
         , x > 0
x = -2
Lastly,, check if the solution is in the defined range to find your final answer.
x = 2
This means that the correct answer to your question is x = 2.
Let me know if you have any further questions
:)
5 0
3 years ago
Read 2 more answers
what is the width of a rectangular prism when the surface area is 904 square feet, and it has a height of 10 feet and a length o
k0ka [10]

Answer:

The answer

Step-by-step explanation:

the width of a rectangular prism which has a height of 10 feet and a length of 14 feet should be 140 square feet

7 0
3 years ago
Help plz...........................
stich3 [128]

Answer:So its simple just forget about the letters add the numbers then place the letter and x

Step-by-step explanation: ( Always Parentheses first) Then i think you divide it by the outside number

4 0
3 years ago
Read 2 more answers
Two children own two-way radios that have a maximum range of 3 miles. One leaves a certain point at 1:00 P.M., walking due north
Grace [21]

Answer:

The answer is 21 minutes

Step-by-step explanation:

We use the equation Xf = Xo + vt

1) At 1:00 PM, child one leaves the starting point heading north at a constant velocity of 6 mi/hr or .1 [mi/min] (divide by 60 to convert from [mi/hr] to [mi/min])

2) He walks for 15 minutes before kid 2 starts walking. In 15 minutes he is able to cover 1.5 [mi]

  • x_{1f1} =x_{o} +v_{1} t_{1} \\x_{1f1} =0+.1(15)\\x_{1f1} =1.5 [mi]

3) Now, child 2 starts walking and we know that when the range reaches 3 miles, they won´t be able to communicate. So the sum of the final position of child 1 and child 2 must be 3[mi]

  • Child 1 final position => x_{1f} = x_{1f1} +v_{1} t\\x_{1f} =1.5+v_{1} t
  • Child 2 final position => x_{2f} =0+v_{2} t

4) Sum the equations and equate to 3

  • x_{1f} +x_{2f} =3

5) Substitute the values we already know

  • 1.5+v_{1} t+v_{2}t=3\\ 1.5+.1t+.15t=3\\1.5+.25t=3\\t=\frac{3-1.5}{.25} \\t=6 [min]

6) in 15 + 6 minutes they will be 3miles apart

7) In 21 minutes they will still be able to communicate with one another.

7 0
3 years ago
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