Question

A rectangle has a length that is 4 units longer than the width. If the width is increased by 7 units and the length increased by 5 units, write an equivalent expression for the area of the rectangle. Group of answer choices

Answer 1

Answer:

A = (x + 7)(x + 9)

Step-by-step explanation:

Let the width w = x

then length l = w + 4 = x + 4

Area =  length x width

        = x(x+4)

Then the the width is increased by 7 units and the length increased by 5 units.

w = x + 7

l = (x + 4) + 5 =x + 9

A = (x + 7)(x + 9)

Answer 2

Answer:

Area of rectangle = length × Width

In this case

Assuming "w" as the width of rectangle,

Area = (w +9) (w +7)

Step-by-step explanation:

Let "w" be the width of rectangle,

so

length = w + 4, as it is 4 units greater.

Width = w

Now after adding 5 units in length and 7 units in width, now our measurments will be,

length = w +4 +5 = w+9

width = w+7.

So now area will be

A = (w+9)(w+7).