A rectangle has a length that is 4 units longer than the width. If the width is increased by 7 units and the length increased by
5 units, write an equivalent expression for the area of the rectangle. Group of answer choices
2 answers:
Answer:
A = (x + 7)(x + 9)
Step-by-step explanation:
Let the width w = x
then length l = w + 4 = x + 4
Area = length x width
= x(x+4)
Then the the width is increased by 7 units and the length increased by 5 units.
w = x + 7
l = (x + 4) + 5 =x + 9
A = (x + 7)(x + 9)
Answer:
Area of rectangle = length × Width
In this case
Assuming "w" as the width of rectangle,
Area = (w +9) (w +7)
Step-by-step explanation:
Let "w" be the width of rectangle,
so
length = w + 4, as it is 4 units greater.
Width = w
Now after adding 5 units in length and 7 units in width, now our measurments will be,
length = w +4 +5 = w+9
width = w+7.
So now area will be
A = (w+9)(w+7).
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Step-by-step explanation:
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3/4 as a fraction to 9/12
Answer:
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