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Alina [70]
2 years ago
8

Determine the equation of the perpendicular bisector of the segment with endpoints (–5, 3) and (5, 5).

Mathematics
1 answer:
Ann [662]2 years ago
4 0

Answer:

y=-5x+4

Step-by-step explanation:

First lets find the midpoint of the points (-5,3) and (5,5).

(0,4) is the midpoint by the midpoint formula.

Next we find the slope of the 2 points.

2/10 or 1/5

To find the perpendicular bisector, we need to find the negative reciprocal of the slope, which is -5x. However, we want the line to pass through (0,4), so we make the y-intercept 4.

Therfore, the answer is y=-5x+4

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each of the letters of the word ALABAMA is written on a piece of paper and then put into a bag. A piece of paper is drawn at ran
Yanka [14]

Answer:

P(A) = 0.57 (to the nearest hundredth)

Step-by-step explanation:

There are 7 letters in total

4 of them are the letter A

⇒ P(A) = 4/7

           = 0.5714285714...

           = 0.57 (to the nearest hundredth)

5 0
3 years ago
Please answer ASAP (Will mark brainliest!!!) :Which of the following ordered pairs represents the x-intercept of the equation y
andreyandreev [35.5K]
To get the x-intercept you put y=0

0=2x-8

2x=8 , x=4

the point is (4,0)
8 0
4 years ago
Read 2 more answers
How do you do this question?
alina1380 [7]

Answer:

(8√2) / 15

Step-by-step explanation:

A curve bounded by the y-axis is represented by in terms of dy;

\int \:x\:dt

When the curve crosses the y-axis, x will be 0. In this case x is the function of t, so we have to solve for x(t) = 0;

0 = t^2 + 2t --- (1)

Solution(s) => t = 0, t = 2

dy = (1/2 * 1/√t)dt --- (2)

Our solutions (0, 2) are our limits. The area of the curve is in the form A\:=\:\int _b^a\:f\left(t\right)g'\left(t\right)dt , so now let's introduce the limits of integration, x(t) and dy/dt. Remember, dy/dt = (1/2 * 1/√t) (second equation). 1/2 * 1/√t can be rewritten as 1/2 * t^(-1/2)....

A\:=\:\int _2^0\:\left(t^2-2t\right)\left(\frac{1}{2}t^{-\frac{1}{2}}\right)dt\\\\= \int _2^0\:\left(\frac{1}{2}t^{\frac{3}{2}}-t^{\frac{1}{2}}\right)dt\\\\= \left[\frac{t^{\frac{5}{2}}}{5}-\frac{2t^{\frac{3}{2}}}{3}\right]_2^0\\\\= 0\:-\:\left(\frac{4\sqrt{2}}{5}-\frac{4\sqrt{2}}{3}\right)\\\\= \frac{8\sqrt{2}}{15}

Your solution is 8√2 / 15

7 0
3 years ago
I need help with this, ASAP.
Arada [10]

This is the answer. Always remember SOH CAH TOA

Had fun solving this ngl

7 0
3 years ago
8+10x-2+x+3 what is the answer
SIZIF [17.4K]

Answer:

  9 + 11x

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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