→ Substitute cos 2x and sin 2x by their expressions
→ Subtract both sides by sin x
→ Take sin x as a common factor in the right side
From the graph, the equation has 4 solutions, the intersection points between the 2 graphs
Determine the equation of the perpendicular bisector of the segment with endpoints (–5, 3) and (5, 5).
1 answer:
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They are perpendicular because when you change 2x+8y=16 to slope intercept form it becomes y= -1/4x+2 and the slope (-1/4) is the negative reciprocal of 4, which is the slope for your other equation.
Please comment if you have any questions :)
Please comment if you have any questions :)
We are given equations as
Firstly, we will write in slope intercept form of line
y=mx+b
Subtract both sides by 4x
now, we can divide both sides by a
we can find slope
so, we get
we are given second equation as
Firstly, we will write in slope intercept form of line
y=mx+b
divide both sides by a
we can find slope
we are given both lines are perpendicular
so, the multiplication of their slopes must be -1
we can plug values
now, we can solve for a
Multiply both sides by a
now, we can solve for a
we get
...............Answer