The answer to this problem please

Mathematics

1 answer:

MatroZZZ [7]3 years ago

3 0

Ya I Know the ans but your points are very less so I m not intrusted to give Answer

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What are the solution(s) of x2-4-0?

Elanso [62]

Answer:

For $x^2 - 4 = 0$ , x = 2, or x = - 2.

Step-by-step explanation:

Here, the given expression is :

$x^2 - 4 = 0$

Now, using the ALGEBRAIC IDENTITY:

$a^2 - b^2 = (a-b)(a+b)$

Comparing this with the above expression, we get

$x^2 - 4 = 0 = x^2 - (2)^2 = 0\\\implies (x-2)(x+2) = 0$

⇒Either (x-2) = 0 , or ( x + 2) = 0

So, if ( x- 2) = 0 ⇒ x = 2

and if ( x + 2) = 0 ⇒ x = -2

Hence, for $x^2 - 4 = 0$ , x = 2, or x = - 2.

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Answer: $15

Step-by-step explanation:

To find the markup price just multiply 30% by the amount.

30% * 50

0.3 * 50 = 15

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How to change 3 7/8 into an improper fraction

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3 7/8

So we can use this $a \frac{b}{c} = \frac{(a \times c) + b}{c}$

So we get

$3 \frac{7}{8} = \frac{(3 \times 8) + 7}{8}$

= $\frac{24+7}{8} = \frac{31}{8}$