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Sati [7]
3 years ago
10

Select one answer choice For part A and select one answer choice for part B

Mathematics
1 answer:
sweet [91]3 years ago
6 0

\bf \qquad \qquad \qquad \textit{discriminant of a quadratic} \\\\\\ \stackrel{\stackrel{a}{\downarrow }}{1}x^2\stackrel{\stackrel{b}{\downarrow }}{+6}x\stackrel{\stackrel{c}{\downarrow }}{+9}=0 ~~~~~~~~ \stackrel{discriminant}{b^2-4ac}= \begin{cases} 0&\textit{\underline{one real solution}}~~\textit{\Large \checkmark}\\ positive&\textit{two real solutions}\\ negative&\textit{no solution} \end{cases} \\\\\\ 6^2-4(1)(9)\implies 36-36\implies 0

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It would be 96 because V=(9)(32)= 288/3=96
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Geometric mean is used to determine the scale of objects.<br><br> False<br><br> True
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In a certain Algebra 2 class of 27 students, 18 of them play basketball and 16
Bogdan [553]

Answer:

<em>The probability is 0.89 or 89%</em>

Step-by-step explanation:

<u>Probability</u>

There are n=27 students in a certain Algebra 2 class. 18 out of them play basketball and 16 of them play baseball.

We also know 3 students play neither sport. This leaves 27-3=24 students playing sports.

The probability that a randomly chosen student plays basketball or baseball is:

\displastyle p=\frac{24}{27}

Simplifying:

\displastyle p=\frac{8}{9}=0.89

The probability is 0.89 or 89%

6 0
3 years ago
Please help ASAP I NEED THIS TOMORROW!!!
Mama L [17]
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7 0
3 years ago
Use the graph below to determine a1 and d for the sequence. graphed sequence showing point 1, negative 10, point 2, negative 7,
Sonja [21]

Answer:

a_1=-10

d=3

Step-by-step explanation:

we know that                              

In an <u><em>Arithmetic Sequence</em></u> the difference between one term and the next is a constant, and this constant is called the common difference (d)

In this problem we have the ordered pairs

(1,-10),(2,-7),(3,-4),(4,-1),(5,2),(6,5)                      

Let                                          

a_1=-10\\a_2=-7\\a_3=-4\\a_4=-1\\a_5=2\\a_6=5

Find the difference between one term and the next

a_2-a_1=-7-(-10)=3              

a_3-a_2=-4-(-7)=3                  

a_4-a_3=-1-(-4)=3                        

a_5-a_4=2-(-1)=3                              

a_6-a_5=5-2=3                                                        

The difference between one term and the next is a constant        

This constant is the common difference                  

so                                                                                                                                  

The sequence graphed is an Arithmetic Sequence                    

therefore                                                                                    

The first term is a_1=-10                                    

The common difference is equal to d=3          

4 0
3 years ago
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