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user100 [1]
3 years ago
13

Under certain conditions the pressure of a gas varies directly with the temperature. When the pressure is 900 psi, the temperatu

re is 350. What is the pressure when the temperature is 70?
Mathematics
1 answer:
Crank3 years ago
8 0

Answer:

180psi

Step-by-step explanation:

Step one:

given data

P1= 900 psi

T1= 350°C

P2=?

T2=70°C

Required

The final pressure P2

<em>Gay-Lussac's Law: The Pressure Temperature Law. This law states that the pressure of a given amount of gas held at constant volume is directly proportional to the Kelvin temperature. With an increase in temperature, the pressure will go up</em>

Applying the expression

P1/T1= P2/T2

substitute:

900/350= P2/70

2.57=P2/70

cross multiply

P2= 2.57*70

P2=180psi

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Answer:

A. 4".

B. Approximately 9.54".

C. Approximately 13.54".

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Please find the attachment.

Let x be the distance from the peak of the kite to the intersection of the diagonals and y be the distance from the peak of the kite to the intersection of the diagonals.

We have been given that two sides of a kite are 10 inches and two sides are 5 inches. The shorter diagonal is 6 inches.

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We can see from our attachment that point O is the intersection of both diagonals. In triangle AOD the side length AD will be hypotenuse and side length DO will be one leg.

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x^{2}=25-9

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Upon taking square root of both sides of our equation we will get,

x=\sqrt{16}

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Since distance can not be negative, therefore, the distance from the peak of the kite to the intersection of the diagonals is 4 inches.

B. We can see from our attachment that point O is the intersection of both diagonals. In triangle DOC the side length DC will be hypotenuse and side length DO will be one leg.

We can find the value of y using Pythagorean theorem as:

(OC)^2=(DC)^2-(DO)^2

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y^2=10^2-3^2

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y^2=91

Upon taking square root of both sides of our equation we will get,

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Since distance can not be negative, therefore, the distance from intersection of the diagonals to the top of the tail is approximately 9.54 inches.

C. We can see from our diagram that the length of longer diagram will be the sum of x and y.

\text{The length of the longer diagonal}=x+y

\text{The length of the longer diagonal}=4+9.54

\text{The length of the longer diagonal}=13.54

Therefore, the length of longer diagonal is approximately 13.54 inches.

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