Answer:
Step-by-step explanation:
the arrows from the picture tells us that TV is parallel to RS
since TS is a transversal that cuts the 2 parallel lines TV and RS than ∠S =x
(alternate interior angles)
sum of angles in a Δ is 180° so x+x+2x = 180°, 4x =180°, x= 45°
2x = 45*2 = 90°
This isn’t a question this is just a statement
Answer: 135 days
Step-by-step explanation:
Since the amount of time it takes her to arrive is normally distributed, then according to the central limit theorem,
z = (x - µ)/σ
Where
x = sample mean
µ = population mean
σ = standard deviation
From the information given,
µ = 21 minutes
σ = 3.5 minutes
the probability that her commute would be between 19 and 26 minutes is expressed as
P(19 ≤ x ≤ 26)
For (19 ≤ x),
z = (19 - 21)/3.5 = - 0.57
Looking at the normal distribution table, the probability corresponding to the z score is 0.28
For (x ≤ 26),
z = (26 - 21)/3.5 = 1.43
Looking at the normal distribution table, the probability corresponding to the z score is 0.92
Therefore,
P(19 ≤ x ≤ 26) = 0.92 - 28 = 0.64
The number of times that her commute would be between 19 and 26 minutes is
0.64 × 211 = 135 days
<h3>
Answer: Yes they are equivalent</h3>
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Work Shown:
Expand out the first expression to get
(a-3)(2a^2 + 3a + 3)
a(2a^2 + 3a + 3) - 3(2a^2 + 3a + 3)
2a^3 + 3a^2 + 3a - 6a^2 - 9a - 9
2a^3 + (3a^2-6a^2) + (3a-9a) - 9
2a^3 - 3a^2 - 6a - 9
Divide every term by 2 so we can pull out a 2 through the distributive property
2a^3 - 3a^2 - 6a - 9 = 2(a^3 - 1.5a^2 - 3a - 4.5)
This shows that (a-3)(2a^2 + 3a + 3) is equivalent to 2(a^3 - 1.5a^2 - 3a - 4.5)
