Answer:
Are you doing Iready?
Step-by-step explanation:
If so, I can't help you, and neither can anyone else.
Answer:
and 
Step-by-step explanation:
Assume that the terminal side of thetaθ passes through the point (−12,5).
In ordered pair (-12,5), x-intercept is negative and y-intercept is positive. It means the point lies in 2nd quadrant.
Using Pythagoras theorem:
Taking square root on both sides.
In a right angled triangle
In second quadrant only sine and cosecant are positive.
and
Answer: a is the # of elements in A but NOT B, that is A ONLY
b is the # of elements in B but NOT A, that is B only
N is the # of elements in the INTERSECTION of A and B
a + N = 99
b + N = 25
a + b + N = 123
Subtracting the first two equations: a - b = 74
Subtracting the last two equations: -a = -98
a = 98
So then a - b = 74 and a = 98
98 - b = 74
-b = -24
b = 24
a = 98, b = 24 and a + b + N = 123
98 + 24 + N = 123
122 + N = 123
N = 1
98 are in A only
24 are in B only , which is the answer to the question
1 is in both A and B
Step-by-step explanation:
Answer:
Two angles of a quadrilateral : 220 and 90 deg.
The other two angles (x and y) are in ratio 2:3.
We have:
x + y = 360 - 220 - 90 = 50 (property of sum of 4 angles in quadrilateral)
x/y = 2/3 => x = 2y/3
=>2y/3 + y = 50
=> 5y/3 =50
=> 5y = 150
=> y = 30
=> x = 2 x 30/3 = 20
=> Two other angles are 20 and 30 deg
Hope this helps!
:)
It's a flat horizontal line so the slope is 0
Slope = rise/run = 0/run = 0
The "run" can be any number you want as long as it's not 0.
